Answer:
Option C.
Step-by-step explanation:
Given information: In triangle ABC, ST║AC, SB=10 ft, BT=9 ft and CT=2.7 ft.
Triangle proportionality theorem: If a line segment parallel to a side of a triangle then the line segments divides the remaining sides proportionally.
Using triangle proportionality theorem we get


On cross multiplication we get


Divide both sides by 9.

The length of SA is 3ft.
Therefore, the correct option is C.
Answer:
Step-by-step explanation:
Given the first two numbers of a sequence as 2, 6...
If it is an arithmetic difference, the common difference will be d = 6-2 = 4
Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d
a is the first term = 2
d is the common difference = 4
n is the number if terms
Substituting the given values in the formula.
Nth term Tn = 2+(n-1)4
Tn = 2+4n-4
Tn = 4n-4+2
Tn = 4n-2
2) If the sequence us a geometric sequence
Nth term of the sequence Tn = ar^(n-1)
r is the common ratio
r is gotten by the ratio of the terms I.e
r = T2/T1
r = 6/2
r = 3
Since a = 2
Tn = 2(3)^(n-1)
Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)
Answer: if you are going to put it like p^2-m^2 no one going to have that answer so I need the p and the m like for example the p=5 and the m=4
Step-by-step explanation: so it going to be like
Evaluate for m=4,p=5
5^2−4^2
=9
So I can’t answer how you put it
Answer:
C. The difference of the medians is 4 times the interquartile range.
Step-by-step explanation:
The diagram show two box plots.
<u>Mahoney's box plot:</u>
Median 
Interquartile range 
<u>Martin's box plot:</u>
Median 
Interquartile range 
The interquartile ranges are the same.
The difference of the medians 
Hence, the difference of the medians is 4 times the interquartile range.
Answer:
x = 150°
Step-by-step explanation:
The given parameters are;
AB ║ DC
∠BAE = 105°
∠AEC = 25°
We construct a line CF from C parallel to the line AE as presented in the included diagram created with Microsoft Visio
We have;
∠DCF ≅ ∠BAE = 105° by similar angles formed by two pairs of parallel lines
∠AEC = ∠ECF = 25° by alternate interior angles formed by two parallel lines and a common transversal
x = 125° + 25° = 150° By angle addition postulate
x = 150°.