How do u turn y-4=5/3(x+3) into standard form

Mathematics

1 answer:

BARSIC [14]3 years ago

7 0

well, bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

so hmmm we have a fraction.... so let's multiply both sides by the LCD of all fractions to do away with denominators, hmmm say the LCD will just be 3, so we'll multiply both sides by that

$\bf y-4=\cfrac{5}{3}(x+3)\implies y-4=\cfrac{5(x+3)}{3}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-4)=3\left( \cfrac{5(x+3)}{3} \right)} \\\\\\ 3y-12=5(x+3)\implies 3y-12=5x+15\implies 3y=5x+27 \\\\\\ -5x+3y=27\implies 5x-3y=-27$

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