Answer:
top left
Step-by-step explanation:
take a vertical line and place it on the graph. Then no matter where on the graph you place the vertical line, the graph should only cross the vertical line once. ( it only crossed once)
Given the Scale of the Drawing as 3 : 1000
It means in the Drawing a Length of 3cm is Equal to 1000cm of the Actual Pool
It means in the Drawing a Length of 3cm is Equal to 10m of the Actual Pool
Given the Length of the Pool in the Drawing is 15cm
⇒ Actual Length of the Pool is 5 × 10m = 50m
Given the Width of the Pool in the Drawing is 7.5cm
⇒ Actual Width of the Pool is 2.5 × 10m = 25m
We know that Area of Rectangular Pool is Length × Width
⇒ Area of the Rectangular Pool = 50 × 25 = 1250m²
Answer:
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Step-by-step explanation:
Since we have the radius of the sphere R = 4, we have R² = r² + z² where r = radius of cylinder in z-plane and z = height² of cylinder.
So, r = √(R² - z²)
r = √(4² - z²)
r = √(16 - z²)
Since the region is above the plane z = 2, we integrate z from z = 2 to z = R = 4
Our volume integral in cylindrical coordinates is thus
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π