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3 years ago

PLEASE HELP! WILL MARK BRAINLIEST!! :D

Mathematics

1 answer:

netineya [11]3 years ago

6 0

Hope this helps

Given a term in a geometric sequence and the common ratio find the first five terms, the explicit formula, and the recursive formula. Given two terms in a geometric sequence find the 8th term and the recursive formula. Determine if the sequence is geometric. If it is, find the common ratio.

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I need to find the missing angle measures.

scoray [572]

Answer:

step 1. b = 102° (vertical angles)

step 2. one complete revolution equals 360°

step 3. a + b + c + 102 = 360

step 4. a + 102 + c + 102 = 360

step 5. a + c = 156°

step 6. 2a = 156 (vertical angles are equal)

step 7. a = 78°, c = 78°.

4 0

3 years ago

x + y = 6. 2x - y = 3. The system of equations. . . a.has no solution. b.has one solution. c.is coincident

balu736 [363]

Answer:

<u>The answer is the option B</u>

The system has one solution

Step-by-step explanation:

we have

$x+y=6$ ------> equation A

$2x-y=3$ ------> equation B

Adds equation A and equation B

$x+y=6\\2x-y=3\\-------\\2x+x=6+3\\3x=9\\x=3$

Find the value of y

Substitute the value of x in equation A or equation B

$3+y=6$

$y=3$

therefore

The system has one solution

8 0

3 years ago

Read 2 more answers

An English teacher needs to pick 1111 books to put on his reading list for the next school year. He has narrowed down his choice

forsale [732]

Answer:

There are 3,659,040 ways he can choose the books to put on the list.

Step-by-step explanation:

There are

12 novels

8 plays

12 nonfiction.

He wants to include

5 novels

4 plays

2 nonfiction

The order in which the novels, plays and nonfictions are chosen is not important. So we use the combinations formula to solve this problem.

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many ways can he choose the books to put on the list?

Novels:

5 from a set of 12. So

$C_{12,5} = \frac{12!}{5!7!} = 792$

Plays:

4 from a set of 8. So

$C_{8,4} = \frac{8!}{4!4!} = 70$

Nonfiction:

2 from a set of 12

$C_{12,2} = \frac{12!}{2!10!} = 66$

Total:

Multiplication of novels, plays and nonfiction.

$T = 792*70*66 = 3,659,040$

There are 3,659,040 ways he can choose the books to put on the list.

4 0

3 years ago

I am so confused. not sure how to solve need step by step instruction to help please

sladkih [1.3K]

Answer:

Step-by-step explanation:

Since -5 is less than zero, we use the second equation, and substitute the -5 in for the x.

-2(-5)+3=13

7 0

3 years ago

A researcher is interested in estimating the mean blood alcohol content of people arrested for driving under the influence. Base

UNO [17]

Answer:

We need a sample size of at least 650

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem:

We need a sample of size at least n

n is found when $M = 0.005, \sigma = 0.065$

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.005 = 1.96*\frac{0.065}{\sqrt{n}}$

$0.005\sqrt{n} = 1.96*0.065$

$\sqrt{n} = \frac{1.96*0.065}{0.005}$

$(\sqrt{n})^{2} = (\frac{1.96*0.065}{0.005})^{2}$

$n = 649.23$

Rounding up

We need a sample size of at least 650

7 0

3 years ago