The one of the left isn't too tricky, in the bottom left of it you have 1/2 of 1/4 of the shape, and on the bottom right you have 1/4 of 1/4. Imagine the whole shape was cut up like that bottom right bit into 16 triangles, then you would have three of them shaded (see my diagram).
The one on the right seems like guesswork to me, so I'm sorry if I'm wrong. It look like you just have to use your eyes to work out how much of the bottom half of the shape is shaded: looks like 1/16 to me (i.e. you can draw four of those along and four down, again, see my diagram.) So plus the top half, which is 8/16, you get 9/16.
Answers: left picture: 3/16.
right picture: 9/16.
Option 3:
m∠ABC = 66°
Solution:
Given and ABH is a transversal line.
m∠FAB = 48° and m∠ECB = 18°
m∠ECB = m∠HCB = 18°
<u>Property of parallel lines:
</u>
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠FAB = m∠BHC
48° = m∠BHC
m∠BHC = 48°
<u>Exterior angle of a triangle theorem:
</u>
<em>An exterior angle of a triangle is equal to the sum of the opposite interior angles.</em>
m∠ABC = m∠BHC + m∠HCB
m∠ABC = 48° + 18°
m∠ABC = 66°
Option 3 is the correct answer.
Answer:
the equation of the line is y = -3x - 6
Step-by-step explanation:
Note that since (0, -6) is the y-intercept, we can write the slope-intercept equation of the line as y = mx - 6. The other given point is (-2, 0) (which happens to be the x-intercept also). Starting with y = mx - 6, replace y with 0 and x with -2:
0 = m(-2) - 6. We now solve this for the slope, m: 0 = -2m - 6 becomes
2m = -6, or m = -3.
With m = -3 and b = -6, the equation of the line is y = -3x - 6