(–8) • (6) – (5) • (–2)
= (-8*6)-(5*-2)
= (-48)-(-10)
= -48+10
= -38
(–4) • (9) – (5) • (–2)
= (-4*9)-(5*-2)
= (-36)-(-10)
= -36+10
= -26
Evaluate 3(a – 4b) when a = –2 and b = 5.
= 3[-2 - 4(5)]
= 3[-2 -20]
= 3(-22)
= -66
Evaluate 4(a – 3b) when a = –4 and b = 6.
= 4[-4 - 3(6)]
= 4[-4 -18]
= 4(-22)
= -88
Evaluate 5(a – 2b) when a = –3 and b = 5.
= 5[-3 - 2(5)]
= 5(-3 - 10)
= 5(-13)
= -65
The length of any right angled triangle's hypotenuse is the square root of the squares of the other two sides.
a^2+b^2=c^2
Answer:
(-10, 3)
Step-by-step explanation:
You can do it algebraically (substitution or elimination) or graphically. I will be using substitution to solve this.
Step 1: Rewrite 2nd equation
2y = 6
y = 3
Step 2: Plug in <em>y</em>
7x + 8(3) = -46
7x + 24 = -46
7x = -70
x = -10
Put it in coordinates and we have our final answer!
Answer:
56
Step-by-step explanation:
80 x (7 / 10) = 56