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koban [17]
3 years ago
6

What is the value for B, after the equation A=3/7(B-25) is rearranged?

Mathematics
2 answers:
Tom [10]3 years ago
8 0
To find B in terms of A (i hope this is what you want!) you can first multiply 3/7(B-25) by the reciprocal of 3/7, that being 7/3. You now have 7/3A=B-25, and through adding 25 on both sides, you have B=7/3A+25.

Hope this helps!
marta [7]3 years ago
5 0

Answer:

B=\frac{7A}{3}+25

Step-by-step explanation:

We have been given an equation A=\frac{3}{7}(B-25). We are asked to find the value of B for our given equation.

Upon multiplying both sides of our equation by \frac{7}{3}, we will get:

\frac{7}{3}*A=\frac{7}{3}*\frac{3}{7}(B-25)

\frac{7}{3}*A=B-25

\frac{7A}{3}+25=B-25+25

\frac{7A}{3}+25=B

B=\frac{7A}{3}+25

Therefore, the value of B is \frac{7A}{3}+25.

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