Question

What is the value for B, after the equation A=3/7(B-25) is rearranged?

Answer 1

To find B in terms of A (i hope this is what you want!) you can first multiply 3/7(B-25) by the reciprocal of 3/7, that being 7/3. You now have 7/3A=B-25, and through adding 25 on both sides, you have B=7/3A+25.

Hope this helps!

Answer 2

Answer:

$B=\frac{7A}{3}+25$

Step-by-step explanation:

We have been given an equation $A=\frac{3}{7}(B-25)$. We are asked to find the value of B for our given equation.

Upon multiplying both sides of our equation by $\frac{7}{3}$, we will get:

$\frac{7}{3}*A=\frac{7}{3}*\frac{3}{7}(B-25)$

$\frac{7}{3}*A=B-25$

$\frac{7A}{3}+25=B-25+25$

$\frac{7A}{3}+25=B$

$B=\frac{7A}{3}+25$

Therefore, the value of B is $\frac{7A}{3}+25$.