Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
Answer:
SA= 902.88 yd²
V = 1386.24 yd³
Step-by-step explanation:
Surface area
Since the bases are right triangles, you need to find the base of the triangle. Use Pythagorean theorem as you are given the hypotenuse and one leg.
19² = 15.2² + b²
361 = 231.04 + b²
Subtract 231.04 from both sides
b² = 129.96
Root that
b = 11.4
Now that you have the base, find the areas of the triangles and rectangles.
<em>Triangles</em> - (15.2*11.4)1/2 (2)
15.2*11.4 = 173.28
<em>Rectangles </em>- (15.2)(16) = 243.2
(16)(11.4) = 182.4
(16)(19) = 304
Add them all together and the SA equals 902.88 yd²
Volume
V = Bh
V = 1/2(15.2)(11.4)(16)
V = 1/2 (2772.48)
V = 1386.24 yd³
Answer:
the answer is |−70 − 15| = |−85| = 85 units [ C ]
hope this helps :)
Step-by-step explanation:
You would take the beginning number and subtract the second number then you would take the number you got and divide it by the first number.
1420-1022=y then y/1420
