I think the answer will be x= 4.4 and y= 2 .
Answer: The first and second options are random samples.
First, assign numbers and drawing the number from a bowl would be a great way to get a random sample. Everyone has the same chance of being selected.
Second, using an alphabetical order is just like the first choice. The chances are the same for everyone.
However, in the third choice, you won't get a random sample. You will get an old and young group. Not a random group of the population.
Answer:
x=-10
Step-by-step explanation:
since there's a given 120 degrees, and it's a isosceles triangle, we know that the line adds up to 180 (where the 120 degrees is). so 120+x=180, the interior angle measures 60 degrees. That being said, the 3 angles measure 60 degrees also. now there's a right angle mark on top, so we find the angle of the smaller triangle (near angle 2) by doing 90-60=30 degrees.
angle 2 is said to be x+160, and there's a line, which tells us that they must add to 180.. so x+160+30=180
x+190=180
x=-10.
Answer: uhh lol fix ya handwriting it'll help in the future
Step-by-step explanation:
2. (-2,-24)
(-1,-10)
(0,0)
(1,6)
(2,8)
3.(-2,8)
(-1,3)
(0,0)
(1,-1)
(2,0)
The group paid $ 5250 at first city and $ 6250 at second city
<u>Solution:</u>
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
The hotel charge before tax in the second city was $1000 higher than in the first
Then the charge at the second hotel before tax will be x + 1000
y = x + 1000 ----- eqn 1
The tax in the first city was 8.5% and the tax in the second city was 5.5%
The total hotel tax paid for the two cities was $790
<em><u>Therefore, a equation is framed as:</u></em>
8.5 % of x + 5.5 % of y = 790
0.085x + 0.055y = 790 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.085x + 0.055(x + 1000) = 790
0.085x + 0.055x + 55 = 790
0.14x = 790 - 55
0.14x = 735
<h3>x = 5250</h3>
<em><u>Substitute x = 5250 in eqn 1</u></em>
y = 5250 + 1000
<h3>y = 6250</h3>
Thus the group paid $ 5250 at first city and $ 6250 at second city
