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maria [59]
4 years ago
13

Which of the following situations represents choosing a random sample? Assign each person of the population a number. Put all th

e numbers into a bowl and choose ten numbers. Make a list of everyone in the population and put their names in alphabetical order. Choose every twelfth name. Make a list of everyone in the population and put their names in order of age. Choose the ten youngest and ten oldest people.
Mathematics
1 answer:
Nina [5.8K]4 years ago
7 0
Answer: The first and second options are random samples.

First, assign numbers and drawing the number from a bowl would be a great way to get a random sample. Everyone has the same chance of being selected.

Second, using an alphabetical order is just like the first choice. The chances are the same for everyone.

However, in the third choice, you won't get a random sample. You will get an old and young group. Not a random group of the population.
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AlekseyPX

Answer:

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tino4ka555 [31]

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3 years ago
X= 2 and y = 4, then -X-XY
Fed [463]

Answer:

-10

Step-by-step explanation:

= -X - XY

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5 0
3 years ago
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PLEASE HELP!!!
allsm [11]

Answer/Step-by-step explanation:

Part A: Net A is the correct net. If we decide to fold the net, we'd get the shape of the prism. Folding back net B won't give us the shape of the prism because of the position and arrangement of the right triangular  bases.

Part B:

AB =  3in

BC = 5 in

CD = 9.4 in

Part C: surface area of the prism can be calculated by calculating the area of each part of the net, and summing them together as follows,

Area of the 2 triangular bases = 2(½*base*height of triangle) = 2(½*4*3) = 2*2*3 = 12 in²

Area of the three rectangles =

= (9.4*4) + (9.4*3) + (9.4*5) = 37.6 + 28.2 + 47 = 112.8 in^2

Surface area of prism = 12 + 112.8 = 124.8 in²

4 0
3 years ago
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