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Alchen [17]
3 years ago
9

in 1950 the use of coal in the us was 114.6 million tons. the use of coal has decreased by 6.6% per year since then. estimate th

e amount of coal used in the US in 2010.
Mathematics
2 answers:
Nat2105 [25]3 years ago
8 0
For this problem, it could be mistaken to be decay rate which is exponential. But this is actually logical to simple interest in economics.The difference would be, the principal amount and future amount are interchanged because it is decreasing. Using the formula for simple interest,

Year 1950 = Year 2010 (1 + rate*time)
The time would be 2010-1950 = 60 years

114.6 = x(1 + 0.066*60)
x = 23.1 million tons 
USPshnik [31]3 years ago
6 0

Answer:

Amount of estimated coal that has been used in the year 2010 = 23.1 million tons

Step-by-step explanation:

In 1950 the use of coal in the us was 114.6 million tons

The use of coal has decreased by 6.6% per year since then

The time would be 2010 - 1950 = 60 years  

Let the estimate amount used in the year 2010

⇒ 114.6 = x(1 + 0.066 × 60)

⇒ 114.6 = x × 4.96

⇒ x = 23.1

Therefore, Amount of estimated coal that has been used in the year 2010 = 23.1 million tons

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Tema [17]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

Option A

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Option A:}}\\\\3^{-5}\\\\\rightarrow \frac{1}{3^5}\\\\\rightarrow  \frac{1}{243}\\\\\ \text{This is \textbf{NOT} an integer.}}

⸻⸻⸻⸻

\boxed{\text{Option B:}}\\\\-3^5\\\\\rightarrow -3 * -3 * -3 * -3 * -3 \\\\\rightarrow \boxed{-243}\\\\\\\text{This \textbf{IS} an integer.}

⸻⸻⸻⸻

\boxed{\text{Option C:}}\\\\\frac{1}{3}^{-5} \\\\\rightarrow \frac{1}{(\frac{1}{3})^5}\\\\\rightarrow \frac{1}{\frac{1}{243} }\\\\\rightarrow \boxed{243}\\\\\\\text{This \textbf{IS} an integer.}

⸻⸻⸻⸻

\text{Option \textbf{A} does not simplify into an integer.}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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