
- Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>
- To find - <u>Area </u><u>of </u><u>trapezium</u>
Refer the figure attached ~
In the given figure ,
AB = 25 cm
BC = AD = 15 cm
CD = 13 cm
<u>Construction</u><u> </u><u>-</u>

Now , we can clearly see that AECD is a parallelogram !
AE = CD = 13 cm
Now ,

Now , In ∆ BCE ,

Now , by Heron's formula

Also ,

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

hope helpful :D
Using it's concept, it is found that the domain of the graphed function is given as follows:
D. 
<h3>What is the domain of a function?</h3>
It is the set that contains all possible input values for the function. In a graph, it is given by the values of x.
In this graph, x assumes values between -4 and 2, inclusive due to the closed circle, hence the domain is given by:
D. 
More can be learned about the domain of a function at brainly.com/question/10891721
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Answer:
26.69 square meters
Step-by-step explanation:
A=r(3.14)
A= 8.5(3.14)
A=26.69 meters
Answer:
x=-6
Step-by-step explanation:
"She uses only ___ of those applications"; Please provide the missing information