Over the past year, your friend Maura has been saving up for an epic road trip to travel across the country this summer. Her goa
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Answer:
0.5 seconds (at 100 feet in the air).
Step-by-step explanation:
So, the height of the ball can be modeled by the function:
Where h(t) represents the height in feet after t seconds.
And we want to find its maximum height.
Notice that our function is a quadratic.
Therefore, the maximum height will occur at the vertex of our function.
The vertex of a quadratic function in standard form is given by the formula:
In our function, a=-16; b=16; and c=96.
Find the x-coordinate of the vertex:
So, the ball reaches its maximum height after 0.5 seconds of its projection.
Notes:
To find it’s maximum height, we can substitute 1/2 for our function and evaluate. So:
Evaluate:
So, the ball reaches its maximum height of 100 feet 0.5 seconds after its projection.
Answer:
1327
Step-by-step explanation:
Please check the attachment for explanation.
Solve your equation step-by-step.
5(2y−2)+4=4
Simplify both sides of the equation.
5(2y−2)+4=4
(5)(2y)+(5)(−2)+4=4(Distribute)
10y+−10+4=4
(10y)+(−10+4)=4(Combine Like Terms)
10y+−6=4
10y−6=4
Add 6 to both sides
.
10y−6+6=4+6
10y=10
Divide both sides by 10.
10y/10 = 10/10
5(2y−2)+4=4
Simplify both sides of the equation.
5(2y−2)+4=4
(5)(2y)+(5)(−2)+4=4(Distribute)
10y+−10+4=4
(10y)+(−10+4)=4(Combine Like Terms)
10y+−6=4
10y−6=4
Add 6 to both sides
.
10y−6+6=4+6
10y=10
Divide both sides by 10.
10y/10 = 10/10