Here's the solution,
The given triangle is an <u>equilateral triangle</u>, because it's all angles measure 60° each
now,
Area of an equilateral triangle :
=》
where,
=》
=》
=》
or
=》
Note that
10² = 100
0.08² = 0.0064
and
101.6064 = 100 + 1.6 + 0.0064
It also happens that
1.6 = 2 • 10 • 0.08
which means
101.6064 = 100 + 1.6 + 0.0064
101.6064 = 10² + 2 • 10 • 0.08 + 0.08²
101.6064 = (10 + 0.08)²
101.6064 = 10.08²
which means
√101.6064 = 10.08
which, to one decimal place, is approximately 10.1.
Answer:
The value of x is 2.11
Step-by-step explanation:
area of a triangle=95m^2
perpendicular(p)=3x
base(b)=3x
now,
area of right angled triangle=1/2*b*p
or,95=1/2*3x*3x
or,95*2=9x
or,190=9x
or,190/9=x
x=21.11
The required solution is ∠RQT = 202° and ∠QTS = 51°
<h3 />
<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
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