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3 years ago

003 divided by 6.321

Mathematics

1 answer:

ziro4ka [17]3 years ago

5 0

0.47460844803037 this is the answer

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Derrick's garden is 18 1/2 feet long. he plants bulbs 3/8 of a foot apart. how many bulbs can derrick plant in one row?

Marina86 [1]

He can plant 49 bulbs in one row.

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3 years ago

Find the value of 7! 2!

gregori [183]

Answer: 350% is your answer just 7/2×100= 350%

Step-by-step explanation:

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3 years ago

Plss help i beg you!

frosja888 [35]

Answer:

Step-by-step explanation:

Given expression:

3(x + y) +2x² + (1 + y)²

Find its value when x = 4 and y = 1, substitute:

3(4 + 1) + 2*4² + (1 + 1)² =
3*5 + 2*16 + 2² =
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51

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3 years ago

The lower quartile is the _______ of the lower half of the data set.

Galina-37 [17]

Hey,

The lower quartile is the median of the lower half of the data set.

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3 years ago

In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en

jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

Step(i):-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in Swahili language

n(S) = 125

The probability that the fluent in Swahili language

$P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333$

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in English language

$P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9$

n(E∩S) = 95

The probability that the fluent in English and Swahili

$P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633$

Step(ii):-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

= 0.833+0.9-0.633

= 1.1

Final answer:-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0

3 years ago