Find the absolute maximum and minimum values of f(x.y)=x^2+y^2-2x-2y on the closed region bounded by the triangle with vertices
(0,0), (2,0), and (0,2)
1 answer:
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Answer:
Options (1), (2), (3) and (4)
Step-by-step explanation:
By applying the sine and cosine rules in the given triangle,
sinθ =
cosθ =
cos(30°) =
=
=
sin(30°) =
=
=
cos(60°) =
=
=
sin(60°) = =
=
=
Options (1), (2), (3) and (4) are the correct options.