Answer:

Step-by-step explanation:
<u>Trinomio Cuadrado Perfecto</u>
El producto notable llamado cuadrado de un binomio se expresa como:

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:
* El primer término es un cuadrado perfecto
* El último término es un cuadrado perfecto
* El segundo término es el doble del proudcto de los dos términos del binomio.
Tenemos la expresión:

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:


Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:


Nos cercioramos de que el término central es 2ab:

Operando:

Una vez verificado, ahora podemos decir que:

Answer:
10 i think
Step-by-step explanation:
I think the answer to this is a rate
Answer:
Step-by-step explanation:
x^2=20
just square both sides and u get
x = 4.472135955
Answer:

Step-by-step explanation:
Total number of people = 130
Number of people who use the gym = 73
Number of people who use the pool = 62
Number of people who use the track = 58
Number of people who use the gym and the pool = 22
Number of people who use the pool and the track = 29
Number of people who use the gym and the track = 25
Number of people who use all three facilities = 11
Total number of people who use at least two facilities = 22 + 29 + 25 + 11 = 87
The probability that the randomly selected person uses all three facilities = number of those who use all three facilities ÷ total number of people who use at least two facilities.
==> 11 ÷ 87
==> 