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Lana71 [14]
3 years ago
10

If two polynomial equations have real solutions, then will the equation that is the result of adding, subtracting, or multiplyin

g the two polynomial equations also have real solutions?
Mathematics
2 answers:
Solnce55 [7]3 years ago
5 0
If you graph it,the equation will have a real solution and the solution has to cross the x Axis
dem82 [27]3 years ago
4 0

Answer:

No

Step-by-step explanation:

When adding, subtracting, or multiplying any two polynomial equations that have real solutions, the result will be one polynomial equation and that polynomial equation will be different from the other two, so it may not even have real solutions.

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A study suggested that childrenbetween the ages of 6 and 11 in the US have anaverage weightof 74 lbs. with a standard deviation
Doss [256]

Answer:

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.

This means that \mu = 74, \sigma = 2.7

What proportion of childrenin this age range between 70 lbs and 85 lbs.

This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So

X = 85

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Z = \frac{85 - 74}{2.7}

Z = 4.07

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The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

7 0
2 years ago
How do you determine the square root of a term whose variable(s<br> have exponents greater than 2?
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For higher-degree equations, the question becomes more complicated than others: cubic and quadratic equations  can be solved by similar formulas.

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7 0
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geniusboy [140]

Step-by-step explanation:

Since they have a common denominator the answer is (-5 + 2) / 6 = -3 / 6 = -1/2.

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