Answer:
We have, y=f(x)
From graph, when x = 2, y =f(x)=-5. So, functional value at x=2, f(2) = -5
<h3><u>Solution</u><u>:</u></h3>
Please find the photograph for the square root of 3.
- Firstly, you have to write 3 as 3. 00 00 00.
- Then we should find out the root of the perfect square which is less than 3. Here, 1 is the required perfect square root because 1 × 1 = 1 only which is less than 3.
- Now 3 - 1 = 2 and we are placing 2 zeros after it so that it will be 200. Now we have to add 1 with the divisor 1 which will be 2. Then we have to select a number to be placed beside this 2 in such a way that if we multiply this combined number with the new number, then we will get a number which is less than 200. We see that if we place 7 after 2 and multiply 27 with 7, we get 189 which is less than 200.
- Now 200 - 189 = 11 and we are placing 2 zeros after it so that it will be 1100. Now we have to add 7 with the divisor 27 which will be 34. Then we have to select a number to be placed beside this 34 in such a way that if we multiply this combined number with the new number, then we will get a number which is less than 1100. We see that if we place 3 after 34 and multiply 3 with 343, we get 1029 which is less than 1100.
- Now 1100 - 1029 = 71 and we are placing 2 zeros after it so that it will be 7100. Now we have to add 3 with the divisor 343 which will be 346. Then we have to select a number to be placed beside this 346 in such a way that if we multiply this combined number with the new number, then we will get a number which is less than 7100. We see that if we place 2 after 346 and multiply 2 with 3462, we get 6924 which is less than 7100.
- So, we will get the quotient as 1.732 (corrected to three places of decimal).
4√3
= 4 × 1.732
= 6.928
<h3><u>Answer:</u></h3>
<u>6</u><u>.</u><u>9</u><u>2</u><u>8</u>
Hope it helps
Answer:
![\frac{7}{\sqrt{3}}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B%5Csqrt%7B3%7D%7D)
Step-by-step explanation:
The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:
--------------------(i)
From the question,
the point is (5, 0, -6)
the plane is x + y + z = 6
Therefore,
a = 5
b = 0
c = -6
m = 1
n = 1
t = 1
r = 6
Substitute these values into equation (i) as follows;
![d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |](https://tex.z-dn.net/?f=d%20%3D%20%7C%5Cfrac%7B%28%281%2A5%29%20%2B%20%281%2A0%29%20%2B%20%281%20%2A%20%28-6%29%29%20-%206%29%7D%7B%5Csqrt%7B1%5E2%20%2B%201%5E2%20%2B%201%5E2%7D%7D%20%7C)
![d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |](https://tex.z-dn.net/?f=d%20%3D%20%7C%5Cfrac%7B%28%285%29%20%2B%20%280%29%20%2B%20%28-6%29%20-%206%29%7D%7B%5Csqrt%7B1%20%2B%201%20%2B%201%7D%7D%20%7C)
![d = |\frac{(-7)}{\sqrt{3}} |](https://tex.z-dn.net/?f=d%20%3D%20%7C%5Cfrac%7B%28-7%29%7D%7B%5Csqrt%7B3%7D%7D%20%7C)
![d = \frac{7}{\sqrt{3}}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B7%7D%7B%5Csqrt%7B3%7D%7D)
Therefore, the shortest distance from the point to the plane is ![d = \frac{7}{\sqrt{3}}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B7%7D%7B%5Csqrt%7B3%7D%7D)
Answer:
-36
Step-by-step explanation:
Answer:216
Step-by-step explanation: