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bearhunter [10]
3 years ago
15

What happens to the decimal point when you divide by 10? Question 2 options: moves to the right 1 place moves to the right 2 pla

ces moves to the left 1 place nothing
Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0
When\ dividing\ by\ ten,\ we\ know\ that\ the\ decimal\ always\ moves\ one\\
place\ to\ the\ left.\ Example:\\
10.24 / 10 =  1.024
I hope this helps!
Oduvanchick [21]3 years ago
3 0
When a decimal number is divided by 10 , the decimal point moves to the left one place and a zero will be added to the immediate right side of the decimal point. for instance,if 0.85 is divided by 10, the answer is 0.085
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I need help with this please
enyata [817]

Answer:¿Qué es lo contrario de estos estadistas?

Step-by-step explanation:

What is the opposite of these statesment

5 0
3 years ago
Help please now
Allisa [31]

Answer:

Part A

30

44

26

Part B

176

Step-by-step explanation:

Total: 65+110+75 = 250

P(O) = 75/250 × 100 = 30%

P(A) = 110/250 × 100 = 44%

P(K) = 65/250 × 100 = 26%

Apple juice:

44% of 400

44/100 × 400

176

5 0
4 years ago
Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).
Sliva [168]
To compute the distance between the points, we can apply the distance formula as shown below.

d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5
\overline{AACC} = \sqrt{(9-1)^{2} + (12-1)^{2}} = \sqrt{185}
\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

c^{2} = a^{2} + b^{2} - 2abcosC

or

C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})

Hence, we have

\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})
\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})
\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})

Simplifying this, we have

\angle AA = 36.03^{0}
\angle BB = 126.87^{0}
\angle CC = 17.10^{0} 

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB
3 0
3 years ago
I need help with my homework please answer this correctly I don’t need wrong answers
enyata [817]

Well the 10,000 digit will be 1 and the thousand digit = 7 + 1 = 8

so the first 2 digits are 18

6 fewer than 8 = 2  so we get 182

1 fewer  10 than 1000's is  8-1 = 7  so we have 1827

and  5 fewer ones than 1000.s = 8 - 5 = 3

So our number is 18,273

6 0
3 years ago
Read 2 more answers
if a point is chosen inside the large circle what is the probability that it will also be inside the small circle?
Ira Lisetskai [31]

Answer:

0.25

Step-by-step explanation:

hope that helps! ^w^

8 0
3 years ago
Read 2 more answers
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