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Strike441 [17]
10 months ago
14

Point-lope form for the line that pae through the point (1, –1) and ha a lope of 4

Mathematics
1 answer:
max2010maxim [7]10 months ago
3 0
Answer is
Point-slope form: y + 1 = 4(x -1)
Assuming you wanted
Slope-intercept form: y = 4x -5

Step by step

y - - 1 = 4(x -1)

y + 1 = 4(x -1)

y + 1 = 4x -4

y = 4x -5


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Quadrilateral ABCD has vertices A(1,0) B(5,0) C (7,2) D(3,2). Use slope to prove that ABCD is a parallelogram.
Galina-37 [17]

Answer:

AD \parallel BC

AB \parallel CD

Step-by-step explanation:

The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).

The slope of side AB is

M_{AB}=\frac{0-0}{5-1} =\frac{0}{4}=0

The slope of side BC is

M_{BC}=\frac{2-0}{7-5} =\frac{2}{2}=1

The slope of side CD is

M_{CD}=\frac{2-2}{3-7} =\frac{0}{-4}=0

The slope of AD is

M_{AD}=\frac{2-0}{3-1} =\frac{2}{2}=1

AD \parallel BC

AB \parallel CD

We see that the opposite sides of the quadrilateral ABCD are equal.

Hence the quadrilateral is a parallelogram

4 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
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