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Norma-Jean [14]
3 years ago
12

Please help.... both pictures are the questions

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
5 0
I, thinking 12.45 because if u divide by 6 reaplace the 4 with a 5 it will equal 12.45 for the secondd one at the top
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Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

4 0
3 years ago
Read 2 more answers
Why is it I paid for this app but i am not beneiting from it? will have to get rid! useless​
Leona [35]
You paid ..I’m broke so I can’t lol ..in my opinion it can be helpful sometimes because some of the questions don’t get answered or it’s someone just saying “I don’t know
7 0
3 years ago
The equation of the line with slope = 3, going through point (2, 4) is:
Marina86 [1]

(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\hspace{10em} \stackrel{slope}{m} ~=~ -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-3}(x-\stackrel{x_1}{2}) \\\\\\ y-4=-3x+6\implies y=-3x+10

7 0
2 years ago
Read 2 more answers
In a different plan for area​ codes, the first digit could be any number from 2 through 5​, the second digit was either 2, 3, 4,
GrogVix [38]

Answer:

Step-by-step explanation:

First digit 2,3,4,5 = 4 different digits.

Second digit 2,3,4,5 = 4 different digits.

Third digit = 1,2,3,6,7,9 = 6 different digits.

Total number of possibilities = 4*4*6 = 96

3 0
3 years ago
How do I do this, I need to show work
kenny6666 [7]
Hello,

-2<1 ==> f(x)=3x²-1 =>f(-2)=3*(-2)²-1=3*4-1=12-1=11

3 0
3 years ago
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