Please help.... both pictures are the questions

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

5 0

I, thinking 12.45 because if u divide by 6 reaplace the 4 with a 5 it will equal 12.45 for the secondd one at the top

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Agent Bond is standing on a bridge, 13.5 m above the road below, and his pursuers are getting too close for comfort. He spots a

Scrat [10]

Answer:

Step-by-step explanation:

Eek! Let's give this a go. Things we know:

acceleration of Bond in free fall is -9.8 m/s/s

velocity of the truck is 25 m/s

displacement Bond will travel when he jumps is -10 m

What we are looking for is the time it will take him to hit the top of the truck, knowing that the truck can travel from one pole to the next in 1 second.

Our displacement equation is

Δx = v₀t + 1/2at²

Filling in we have

$-10=25t+\frac{1}{2}(-9.8)t^2$

Simplifying we get

$-10=25t-4.9t^2$

This is a quadratic that needs to be solved however you personally solve quadratics. When you do that, you find that the times it will take Bond to drop that displacement is either -.37 seconds or 5.47 seconds. Many things in physics can be negative, like velocity and acceleration, but time NEVER will be. So it takes Bond 5.5 seconds to drop to the roof of the moving truck. That means that he needs to jump when the truck is between the 5th and the 6th poles away from him.

Good luck with this!

Cheers!

6 0

3 years ago

The coordinates of rectangle ABCD are A(1, 2), B(4, 5),C(9, 0) and D(6, -3). What is the area of the rectangle? 18 square units

Natali5045456 [20]

In order to find the area of a rectangle, the formula is L*W (Length multiplied by Width). Our goal is to find these two measurements, so we will take the following steps:
1) Plot the coordinates on a graph (I have attached a visual guide)
2) Using the Pythagorean Theorem, or the Distance formula we can find the length and width: $\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}$
3) We will use these values in the Area formula for a rectangle (L*W)
4) After solving the Area formula with the values retrieved from the Distance Formula we find that the area is roughly 30 units squared.