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Pepsi [2]
3 years ago
5

Solve 9≥x+15. The solution is ___

Mathematics
2 answers:
joja [24]3 years ago
5 0

Answer:

x is equal to or less than -6

Step-by-step explanation:

9\geq x+15\\-x\geq 15-9\\-x\geq 6\\x\leq -6

Lana71 [14]3 years ago
4 0

Answer: 6

Step-by-step explanation:

15 - 9 = 6 to the quadratics x inequalities formula x b to the power of \int\limits^a_b {x} \, dx

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hammer [34]

the answer is B

because 54x 3= 162 x3 = 486x3= 1458x3=4,374x3=13,122x3=39,366x3=118,098x3=354,294

7 0
3 years ago
Find the value of x so that the shaded region is a gnomon to the white rectangle.
RUDIKE [14]

Based on the shaded region, the value of x which makes this region a gnomon is x = 1.

<h3>What is value of x?</h3>

Based on the dimensions of the side that isn't shaded, and the dimensions of the side that is shaded, the value of x can be found as:

3/ 6 = (1 + 3) / (x + 6 + x)

1/2 =  4 / (6 + 2x)

6 + 2x = 4 / (1/2)

2x = 8 - 6

x = 2/2

x = 1

Find out more on shaded regions at brainly.com/question/9767762.

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4 0
1 year ago
Which function is linear?
Brut [27]

Answer:

f(x)=13x[+4. that one is the Correct answer. I hope it help.

5 0
3 years ago
who else has trouble with math and then gets ridiculed and made fun of by teachers and adults and other, smarter students and th
melomori [17]

Answer:

'''who else has trouble with math and then gets ridiculed and made fun of by teachers and adults and other, smarter students and then just wants to die?''

YES!

3 0
3 years ago
Read 2 more answers
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
4 years ago
Read 2 more answers
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