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3 years ago

Solve 9≥x+15. The solution is ___

Mathematics

2 answers:

joja [24]3 years ago

5 0

Answer:

x is equal to or less than -6

Step-by-step explanation:

$9\geq x+15\\-x\geq 15-9\\-x\geq 6\\x\leq -6$

Lana71 [14]3 years ago

4 0

Answer: 6

Step-by-step explanation:

15 - 9 = 6 to the quadratics x inequalities formula x b to the power of $\int\limits^a_b {x} \, dx$

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Y = 4x-160 is your simplified answer to this question.

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3 years ago

A ship is 5 miles east and 2 miles north away

Yuri [45]

Answer:

Step-by-step explanation:

A ship is 5 miles east and 2 miles north away

from port and then it is 3 miles east and 8

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3 years ago

Please help!!!!<br><br>CE is tangent to this circle, CD is a radius and ECB=48 what is BAC

den301095 [7]

Answer:

48degrees

Step-by-step explanation:

From the circle geometry shown, traingle BDC is an isosceles triangle which shows means that their base angels are the same. Hence;

<B = <C

<CBD + <BCD + <D = 180

<BCD + <BCD + <D =180

2<BCD + <BDC = 180

Get <BCD;

<BCD+ <ECB = 90

<BCD + 48 = 90

<BCD = 90 - 48

<BCD = 42degrees

Get <BDC

2<BCD + <BDC = 180

2(42)+ <BDC = 180

84 + <BDC = 180

<BDC = 180 - 84

<BDC = 96

Since angle at the centre is twice that at the circumference, then;

<BAC = 1/2(<BDC )

<BAC = 96/2

<BAC = 48degrees

4 0

3 years ago

The four-member math team at Pecanridge Middle School is chosen from the math club, which has three girls and five boys. How man

cestrela7 [59]

Answer:

$Total\ Selection = 30\ ways$

Step-by-step explanation:

Given

Girls = 3

Boys = 5

Required

How many ways can 2 boys and girls be chosen?

The keyword in the question is chosen;

This implies combination and will be calculated as thus;

$Selection =\ ^nC_r = \frac{n!}{(n-r)!r!}$

For Boys;

n = 5 and r = 2

$Selection =\ ^5C_2$

$Selection = \frac{5!}{(5-2)!2!}$

$Selection = \frac{5!}{3!2!}$

$Selection = \frac{5 * 4 * 3!}{3!*2 * 1}$

$Selection = \frac{20}{2}$

$Selection = 10$

For Girls;

n = 3 and r = 2

$Selection =\ ^3C_2$

$Selection = \frac{3!}{(3-2)!2!}$

$Selection = \frac{3!}{1!2!}$

$Selection = \frac{3 * 2!}{1 *2!}$

$Selection = \frac{3}{1}$

$Selection = 3$

Total Selection is calculated as thus;

$Total\ Selection = Boys\ Selection * Girls\ Selection$

$Total\ Selection = 10 * 3$

$Total\ Selection = 30\ ways$

5 0

4 years ago

Please help i am stuckkkk, thank you!!!!!

lara31 [8.8K]

What are you stuck with

6 0

3 years ago

Read 2 more answers