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3 years ago

Find the inverse of g(x) = 3x^2 - 5

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

8 0

Answer:

$\boxed{\sf \ \ \ g^{-1}(x)=\sqrt{\dfrac{x+5}{3}} \ \ \ }$

Step-by-step explanation:

Hello,

$x=(gog^{-1})(x)=g(g^{-1}(x))=3(g^{-1}(x))^2-5\\\\3(g^{-1}(x))^2 = x+5\\\\\\ (g^{-1}(x))^2=\dfrac{x+5}{3}\\g^{-1}(x)=\sqrt{\dfrac{x+5}{3}}$

hope this helps

den301095 [7]3 years ago

6 0

Answer: i think its -3x^2 + 5

Step-by-step explanation:

inverses are when you switch the negates, so i'm assuming you switch them.

sorry if i am wrong !

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