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jenyasd209 [6]
3 years ago
7

Estimate, then add. Write each sum in the simplest form.

Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0

Answer:

add the fractions and then divide

Step-by-step explanation:

so you add the top two and then the bottem two and then after you get those two anwsers divide them

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Mia had 5000 In the bank. She keeps the money in the bank for 4 years at 5% interest. How much interest did she earn?
viktelen [127]
Simple interest formula:
Interest = P*R*N

P = principle amount
R = interest rate (in decimal)
N = number of time periods (in years)

Interest = 5000*0.05*4 = $1000
4 0
2 years ago
Given B = {a, l, g, e, b, r} and C = {m, y, t, h}, find B ∪ C. {} {a} {a, b, e, g, h, l, m, r, t, y}
sertanlavr [38]
1. A ∪ B = { x | x ∈ A or x ∈ B} ==> Ans C. 
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3 0
3 years ago
Read 2 more answers
Five times the sum of a number and 3 is the same as 3 multiplied by 1 less than twice the number ​
Aneli [31]

Answer:-2

Step-by-step explanation:

(n + 3) 5 = 3 x 1 - n

distribute so 5n + 15= 3 - n

subtract three from both sides

5n - 12 = -n

subtract 5n from both sides

12 = −6n

Divide both sides by -6

n=-2

7 0
3 years ago
Leasees number from least to greatest 0.5 and 3/16 and 0.5 and 5/48
kumpel [21]
0.5;0.5;3/
16;5/48 that would be how to do it
6 0
4 years ago
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A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer
Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

L_A \to length of play area A

W_A \to width of play area A

L_B \to length of play area B

W_B \to width of play area B

x \to Area of A

y \to Area of B

From the question, we have the following:

L_A = 1 + 4W_A

W_B = 2 + W_A

L_B = 2 + 3W_B

x = y

The area of A is:

x = L_A * W_A

This gives:

x = (1 + 4W_A) * W_A

Open bracket

x = W_A + 4W_A^2

The area of B is:

y = L_B * W_B

y = (2 + 3W_B) * ( 2 + W_A)

Substitute: W_B = 2 + W_A

y = (2 + 3(2 + W_A)) * ( 2 + W_A)

Open brackets

y = (2 + 6 + 3W_A) * ( 2 + W_A)

y = (8 + 3W_A) * ( 2 + W_A)

Expand

y = 16 + 8W_A + 6W_A + 3W_A^2

y = 16 + 14W_A + 3W_A^2

We have that:

x = y

This gives:

W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2

Collect like terms

4W_A^2 - 3W_A^2 + W_A  -14W_A  - 16 =0

W_A^2  -13W_A  - 16 =0

Using quadratic calculator, we have:

W_A = -14.1 or W = 1.13 --- approximated

But the width can not be negative; So:

W = 1.19

7 0
3 years ago
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