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Aloiza [94]
4 years ago
9

Write a class named ParkingMeter containing: An instance variable named timeLeft of type int, initialized to 0. A method named a

dd that accepts an integer parameter. If the value of the parameter is equal to 25, the value of timeLeft is increased by 30; otherwise no increase is performed. add returns a boolean value: true if timeLeft was increased, false otherwise. A method named tick that accepts no parameters and returns no value. tick decreases the value of timeLeft by 1, but only if the value of timeLeft is greater than 0. A method named isExpired that accepts no parameters. isExpired returns a boolean value: true if the value of timeLeft is equal to 0; false otherwise.
Computers and Technology
1 answer:
stealth61 [152]4 years ago
5 0

Answer:

A method named add that accepts an integer parameter. If the value of the parameter is equal to 25

Explanation:

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Today motherboards carry a lot of new functions but the primary functions include controlling input and output of the combined cpu, ram and possibly gpu extension. It also handles fan speeds.
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3 years ago
Write an application that inputs three numbers (integer) from a user. (10 pts) UPLOAD Numbers.java a. display user inputs b. det
SCORPION-xisa [38]

Answer:

The program to this question as follows:

Program:

import java.util.*; //import package for user input

public class Number //defining class Number

{

public static void main(String[] ak)throws Exception //defining main method

{

int a1,b1,c1; //defining integer variable

int p_Count=0,n_Count=0,n_Zero=0,even_Count=0,odd_Count=0;

Scanner obx=new Scanner(System.in); //creating Scanner class object

System.out.println("Input all three numbers: "); //print message

//input from user

a1=obx.nextInt(); //input value

b1=obx.nextInt(); //input value

c1=obx.nextInt(); //input value

//check condition for a1 variable value

if(a1>0) //positive number

p_Count++;

else if(a1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(a1%2==0)//check even number

even_Count++;

else //for odd number

odd_Count++;

//check condition for b1 variable value

if(b1>0) //positive number

p_Count++;

else if(b1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(b1%2==0) //check even number

even_Count++;

else //for odd number

odd_Count++;

//check condition for c1 variable value

if(c1>0) //positive number

p_Count++;

else if(c1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(c1%2==0) //check even number

even_Count++;

else //for odd number

odd_Count++;

//print values.

System.out.println("positive number: "+p_Count);//message

System.out.println("negative number: "+n_Count); //message

System.out.println("zero number: "+n_Zero); //message

System.out.println("even number: "+even_Count); //message

System.out.println("odd number: "+odd_Count); //message

}

}

Output:

Input all three numbers:

11

22

33

positive number: 3

negative number: 0

zero number: 0

even number: 1

odd number: 2

Explanation:

In the above java program code a class is defined in this class three integer variable "a1,b1, and c1" is defined which is used to take input value from the user end, and other integer variable "p_Count=0, n_Count=0, n_Zero=0, even_Count=0, and odd_Count=0" is defined that calculates 'positive, negative, zero, even, and odd' number.

  • In the next step, the conditional statement is used, in if block a1 variable, b1 variable, c1 variable calculates it checks value is greater then 0, it will increment the value of positive number value by 1.
  • else if it will value is equal to 0. if this condition is true it will negative number value by 1
  • else it will increment zero number values by 1.
  • In this code, another if block is used, that checks even number condition if the value matches it will increment the value of even number by 1, and at the last print, method is used that print all variable values.
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3 years ago
A technician is troubleshooting a Windows system in which an application works properly when the computer is booted in Safe Mode
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Answer:

yoooo nba BAD BAD

Explanation:

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3 years ago
How could this code be simplified?
nikklg [1K]

The code to be simplified is not indicated but I will give you a general guide to simplifying Java codes.

<h3>How do you simplify Java Code?</h3>

  1. At the top, declare and initialize your variables. Late declaration disrupts readability.
  2. Create specific functions that are modular. It is inefficient to have functions that attempt to "do it all".
  3. Make it a practice to name the function to correspond to the task.
  4. All duplications must be removed and rectified
  5. Having comments provide a fantastic way to summarize the purpose of a code.
  6. Do not overuse recursion. Doing this makes it difficult to understand at a glance.
  7. If possible, do not use global variables. The local variable takes precedence over the global variable in JavaScript.

Learn more about Java code at;
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Which unique address is a 128-bit address written in hexadecimal?
pentagon [3]
Every hexadecimal digit represents 4 bits, so the address has 128/4 = 32 digits.

A GUID (Globally Unique IDentifier) has 128 bits. They are usually written like this:

{38a52be4-9352-4<span>53e-af97-5c3b448652f0}.</span>

There are different types of guids, depending on how they are generated. The first digit of the third group reveals the type. In the example above it is 4. A type 4 guid is fully random (except of course for the 4).

3 0
3 years ago
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