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Elodia [21]
3 years ago
14

What is the diameter of a circle whose circumference is 62.8 mm? Use 3.14 for π.

Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0
The answer is 20 question
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What is the best approximation of the solutions to the system to the nearest integer values?
Aleksandr-060686 [28]
The first number in the couplet is the distance along the x-axis (i.e. distance from the y-axis).  We can read 0.8 from the graph.
The second number is the distance along the y-axis (i.e.distance from the x-axis).  We can read 6.7 from the graph.

So approximately, we have the point as (0.8, 6.7).
Round the numbers to the nearest integer and you'll get the required answer choice.
4 0
3 years ago
What is the sales price of a $18.95 football with a 15% discount?
skelet666 [1.2K]
$18.95 x 15/100 is equal to 2.84

18.95 - 2.84 is equal to $16.11

Hope that helped! :)
7 0
2 years ago
Read 2 more answers
Can somebody help ??
artcher [175]

Answer:

Step-by-step explanation:

Awnser is 29

It will be nice if you give me brainliest.Good luck!

6 0
3 years ago
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
Zachary travels on a journey of 50 miles. He spends half of
Mars2501 [29]
I divided 50 miles by 2 = 25 miles (walked) 25 miles (horseback)
I divided 25 by 3 = 8.33
I divided 25 by 9 = 3
Added together = 8.33 + 3 = 11.33
So time to complete the journey 11.33 hour
7 0
2 years ago
Read 2 more answers
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