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Elodia [21]
3 years ago
14

What is the diameter of a circle whose circumference is 62.8 mm? Use 3.14 for π.

Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0
The answer is 20 question
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Rhombus JKLM is shown below. Find m∠KLM.
lianna [129]

Answer:

Option D

Step-by-step explanation:

Properties of a rhombus,

1). Diagonals of a rhombus bisect the opposite angles.

2). Sum of adjacent two angles of a rhombus is 180°.

By property (1),

Diagonal JL will bisect the angles ∠MJK and ∠KLM.

Therefore, m∠KLM = 2(5x + 3)°

Similarly, diagonal KM will bisect the angles ∠JKL and JML.

Therefore, m∠JKL = 2(9x - 11)°

By property (2),

2(9x - 11)° + 2(5x + 3)° = 180°

9x - 11 + 5x + 3 = 90

14x - 8 = 90

14x = 98

x = 7

Since, m∠KLM = 2(5x + 3)°

                        = 2(5×7 + 3)°

                        = 76°

Therefore, Option D will be the answer.

7 0
2 years ago
How would i solve this the shaded region is the whole inside circle.​
rosijanka [135]

Answer:

34.48cm²

Step-by-step explanation:

Assuming the shaded area doesn't contain the triangle:

area of triangle = bh/2

area of triangle = 4(2)/2

area = 4

area of circle = πr²

area = π3.5²

area = 38.48

area of shaded = 38.48 - 4

area = 34.48cm²

6 0
1 year ago
Need help with these!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Gelneren [198K]

Answer:

Step-by-step explanation:

8 0
3 years ago
Quadrilateral G, H, I, J has vertices G(-1,2), H(-1,4), I(-2,5) and
bonufazy [111]
I think the answer Is D fame
6 0
2 years ago
Plssss answer! Your team is renting a photo booth for the 8th grade dance, but you have to buy the photo paper and other supplie
Rama09 [41]

Answer:

$215.25

Step-by-step explanation:

4 0
3 years ago
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