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Rashid [163]
4 years ago
5

What's the area of the trapezoid

Mathematics
1 answer:
BlackZzzverrR [31]4 years ago
8 0
46.5cm squared I believe
Hope this helped ;)

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If anyone knows how to report PERSON on brainly please me bc someone is h0m0ph0bc saying lgbtq should go die, keeps using the n
Charra [1.4K]

Step-by-step explanation:

Sadly, users cannot be reported but any content by that person can be reported by pressing the little flag icon. If it doesn't stop after reporting the comments I suggest reaching out to Brainly by Email!

5 0
3 years ago
The time it takes to drive to Joliet is 6 hours more than half the time it takes to drive to Davenport. It takes 8 hours to driv
Molodets [167]
It takes 8 hours to drive to Joliet, and that's 6 hours more than half the time it takes to drive to Davenport. So, I did 8-6 which equals 2. So 2 hours is half the time it takes to get to Davenport, which means it takes 4 hours to get to Davenport. 
6 0
3 years ago
Read 2 more answers
I need the domain range and function. With an explanation
erastovalidia [21]
<h3>Answers:</h3>

Problem 1

  • Domain = -3 < x \le 3, interval notation (-3, 3]
  • Range = -3 \le y < 3, interval notation [-3, 3)
  • Is it a function? Yes

Problem 2

  • Domain = x \ge -2, interval notation [-2, \infty)
  • Range = All real numbers, interval notation (-\infty, \infty)
  • Is it a function? No

Problem 3

  • Domain = -4 \le x < 3, interval notation [-4, 3)
  • Range = -4 < y \le 3, interval notation (-4, 3]
  • Is it a function? Yes

Problem 4

  • Domain = All real numbers, interval notation (-\infty, \infty)
  • Range = y \le 4, interval notation (-\infty, 4]
  • Is it a function? Yes

==================================================

Explanations:

  1. The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore -3 < x \le 3 which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
  2. The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is x \ge -2 which in interval notation is [-2, \infty). The range is (-\infty, \infty) to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
  3. This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
  4. This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is y \le 4 which is the same as saying (-\infty, 4] in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0
4 years ago
What is the simple quotient for 32 divide by 8/5
Softa [21]

Answer:

20

Step-by-step explanation:

32/1 / 8/5= 32/1 x 5/8= 160/8=20

4 0
3 years ago
PLSSS HELP IM DESPERATE!!
Lapatulllka [165]

Answer:

graph c

Step-by-step explanation:

Given

| - 2x | = 4

The absolute value function always gives a positive result, however, the expression inside can be positive or negative , that is

- 2x = 4 or - (- 2x) = 4

Solving both

- 2x = 4 ( divide both sides by - 2 )

x = - 2

or

- (- 2x) = 4

2x = 4 ( divide both sides by 2 )

x = 2

The third graph indicates x = - 2 and x = 2 on the number line

8 0
3 years ago
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