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Rashid [163]
3 years ago
5

What's the area of the trapezoid

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
8 0
46.5cm squared I believe
Hope this helped ;)

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I need help what is 1+1=? I’ll give brainliest to whoever gets it first
ANTONII [103]

Answer:

hmmmm. probably 2? I think it's two

4 0
2 years ago
Read 2 more answers
Its not very clear but if someone could help me with the answers that would be great
Pie
Can’t see it properly...
6 0
2 years ago
1. All of the letters in the alphabet are randomly
Alex
The probability of selecting a vowel from the English alphabet is 5/26 (≈19.2%) if you include only A, E, I, O, and U as vowels
3 0
3 years ago
A right cylinder has a radius of 6 m and a surface area of 84 m². Find the surface area of a similar cylinder with a radius of 2
dlinn [17]

Answer:

The surface area of the second cylinder is equal to 9.33\ m^{2}

Step-by-step explanation:

we know that

If two figures are similar then

the ratio of their surfaces areas is equal to the scale factor squared

Let

z-------> the scale factor

x------> the surface area of the smaller cylinder (second cylinder)

y-------> the surface area of the original cylinder (first cylinder)

so

z^{2}=\frac{x}{y}

Step 1

Find the scale factor

z=\frac{2}{6}=\frac{1}{3}

Step 2

Find the surface area of the second cylinder

we have

z=\frac{1}{3}

y=84\ m^{2}

substitute and solve for x

(\frac{1}{3})^{2}=\frac{x}{84}

x=\frac{1}{9}*84=9.33\ m^{2}


5 0
3 years ago
can you transform the square shown below into pieces that when put together form five small equal squares whose total area shall
Sunny_sXe [5.5K]

How about this (see attached image):

Use the four cuts as shown in the image (red lines).

Then assemble 5 equal squares by the numbers: 1 center square and the rest are pieced together using two pieces as shown. All five together add up to the same area as original square because we use all pieces.

The way one gets a hint toward a solution is to see how an area of a square of length 1 can be split into 5 equal square areas:

1^2 = 5\cdot x^2\\x = \frac{\sqrt{5}}{5} = \sqrt{\frac{2^2}{5^2}+\frac{1^2}{5^2}}

which indicates we need to find a a triangle with sides 2 and 1 to get the hypotenuse of the right length. That gave rise to the cut pattern (if you look carefully, there are triangles with those side lengths).

6 0
3 years ago
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