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3 years ago

Write a comparison sentence to represent this equation 6x7=42.

1 answer:

3 0

A board of length 6 inches and widht 7 inches is divided in equal squares 1 inche side, then the board contains as much as 42 squares

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Presley is organizing the school book sale. Each stall will have 40 books on the shelf and 2 boxes of books with b books inside.

xxMikexx [17]

Okay, I think your saying he has 200 total right, if so then you will say 200-20 over 2, so 180 divided by two = 80 in each box; now- 40s +(2b)s +200 b=12 and s=8 so; 40x8+(2x12)8 + 200
320 +192 +200
712

Presley needs to have 712 books ready.

8 0

4 years ago

A carton has a length of 2 1/4 feet, width of 1 3/5 feet, and height of 2 1/3 feet. What is the volume of the carton?

Alik [6]

Multiply 2 1/4, 1 3/5 and 2 1/3 together! It would be easier to turn these mixed fractions into improper fractions.

5 0

4 years ago

The graph of y = 7x + 56 passes

S_A_V [24]

Answer:

a = 3

Step-by-step explanation:

The point (- 5, 7a ) satisfies the equation

Substitute the coordinate points into the equation and solve for a

7a = 7(- 5) + 56 = - 35 + 56 = 21 ( divide both sides by 7 )

a = 3

3 0

3 years ago

8-c is at most -15 how do i translate this into a sentence?

emmainna [20.7K]

The largest number that 8c could be is -15

3 0

3 years ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

3 years ago