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soldi70 [24.7K]
2 years ago
5

A farmer raises cows and chickens. The farmer had a total of 25 animals. One day he counts the legs of all of his animals and co

unts a total of 64 legs.
Let x = Number of cows
Let y = Number of chickens

Which system of equations can be used to solve for the number of cows and the number of chickens on the farm? PLEASE HELP ILL GIVE BRAINLIEST

Mathematics
1 answer:
-Dominant- [34]2 years ago
7 0
The answer is B because there are 4 legs per cow and 2 per chicken equaling 64 legs, and chickens plus cows are 25 total animals. Hope this helps!
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Question 1
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Answer:

For Lin's answer

Step-by-step explanation:

When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.

Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.

Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.

7 0
2 years ago
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4 feet per second

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Hi there!

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I hope this helps!

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