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soldi70 [24.7K]
3 years ago
5

A farmer raises cows and chickens. The farmer had a total of 25 animals. One day he counts the legs of all of his animals and co

unts a total of 64 legs.
Let x = Number of cows
Let y = Number of chickens

Which system of equations can be used to solve for the number of cows and the number of chickens on the farm? PLEASE HELP ILL GIVE BRAINLIEST

Mathematics
1 answer:
-Dominant- [34]3 years ago
7 0
The answer is B because there are 4 legs per cow and 2 per chicken equaling 64 legs, and chickens plus cows are 25 total animals. Hope this helps!
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(x+y)^2 (x2+2xy+y2) pleas show all work
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Answer:

{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x

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Step-by-step explanation:

1 Use Square of Sum: {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}(a+b)

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({x}^{2}+2xy+{y}^{2})({x}^{2}+2xy+{y}^{2})(x

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2 Expand by distributing sum groups.

{x}^{2}({x}^{2}+2xy+{y}^{2})+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

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3 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

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4 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}({x}^{2}+2xy+{y}^{2})x

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5 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}{x}^{2}+2{y}^{3}x+{y}^{4}x

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6 Collect like terms.

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