The answer of the question is 75
Answer:
A
Step-by-step explanation:
1) first there are a few rules we need to know:
a) the sum of any two sides of a triangle is always larger than the 3rd side
b) the difference between any two sides of a triangle is always smaller than the 3rd side;
hence,
3+4=7
4-3=1
triangle 3,4,5 follows all the rules,
triangle 13,2,11:
11+2=13
the sum of any two sides must always be GREATER than the 3rd side-so this is not an option
triangle 10,4,5
5+4=9
9<10
not an option
What type of teacher would give a frustrating problem like this?!?
First, you need to find the derivative of this function. This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.
f'(x)=3x^2-3
Now, set this function equal to 0 to find x-values of the relative max and min.
0=3x^2-3
0=3(x^2-1)
0=3(x+1)(x-1)
x=-1, 1
To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each. We will use -2, 0, 2.
f'(-2)=3(-2)^2-3=3(4)-3=12-3=9
f'(0)=3(0)^2-3=3(0)-3=0-3=-3
f'(2)=3(2)^2=3(4)-3=12-3=9
We examine the sign changes to determine whether it is a max or a min. If the sign goes from + to -, then it is a maximum. If it goes from - to +, it is a minimum. Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.
To determine the values of the relative max and min, plug in the x-values to f(x).
f(-1)=(-1)^3-3(-1)+1=-1+3+1=3
f(1)=(1)^3-3(1)+1=1-3+1=-1
Hope this helps!!
