Question

Ms.Meyer remarks, "isn't it great? This theater usually charges $9 per student. On Student Night, I can bring 47 more students for the same cost!" How many students can Ms. Meyer bring to the theater?
Tickets: $6

Answer 1

Let's assume

Ms.Meyer used to bring x students for the cost $9 per student

so, total cost = 9x

now, we are given

For ticket cost $6 , she can brings 47 more students

so, total students =x+47

total cost =6*(x+47)

now, we are given total costs are same for both

we get

$9x=6(x+47)$

we can solve for x

$9x=6x+282$

Subtract both sides by 6x

$9x-6x=6x+282-6x$

$3x=282$

Divide both sides by 3

$\frac{3x}{3}=\frac{282}{3}$

$x=94$

so, Ms. Meyer brings 94 students to theatre.........Answer