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Shkiper50 [21]
2 years ago
12

Whoever helps gets brainliest!

Mathematics
2 answers:
lisov135 [29]2 years ago
4 0
<h3>Answer:</h3>

4 miles per hour

<h3>Step-by-step explanation:</h3>

Unit rate is the rate of something per 1 unit. In other words, the unit rate is x units per 1 unit. In this situation, the unit rate is how many miles Hassan walks in 1 hour.

Proportion

First, to find the rate of anything we can set up a proportion. In the question, the rate is described as miles per hour, so the miles will be the numerator and the hours will be the denominator.

  • This creates the proportion \frac{12miles}{3hours}

So, the rate we are given is 12/3.

Unit Rate

To find the unit rate we need to make the denominator equal to 1. To do this, divide both the numerator and denominator by 3.

  • 12/3 equals 4
  • 3/3 equals 1

So, this means that the new proportion is 4/1. Next, we can add our units, which means that Hassan walks 4 miles per 1 hour.

Graph

Now we can resize the bar graph. The purple bar should be set to 4 because this represents the miles. Then, the green bar should be set to 1 because it represents the hours.

wariber [46]2 years ago
3 0
The answer is 4 miles per hour
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2 years ago
(6e-3f-3/4) in a equivalent expression​
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Answer:

Step-by-step explanation:

(6e-3f-3/4) contains two terms which do not involve fractions and one fractional term (3/4).

We can safely remove the parentheses.  Then:

(6e-3f-3/4)  =>  6e - 3f - 3/4

That is "an equivalent expression."

We could go further and create one equivalent fraction.  Multiply the first two terms by 4/4, obtaining:

24e    12f       3           24e - 12f - 3             3(8e - 4f - 1

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  4       4         4                     4                             4

Other equivalent expressions exist here.

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2 years ago
Zach divides 6 cups of fruit juice equally among 8 friends how much fruit juice does each friend get
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3 years ago
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Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
ivanzaharov [21]

Answer:

1508527.582 cm³/min

Step-by-step explanation:

The net rate of flow dV/dt = flow rate in - flow rate out

Let flow rate in = k. Since flow rate out = 6800 cm³/min,

dV/dt = k - 6800

Now, the volume of a cone V = πr²h/3 where r = radius of cone and h = height of cone

dV/dt = d(πr²h/3)/dt = (πr²dh/dt)/3 + 2πrhdr/dt (since dr/dt is not given we assume it is zero)

So, dV/dt = (πr²dh/dt)/3

Let h = height of tank = 12 m, r = radius of tank = diameter/2 = 3/2 = 1.5 m, h' = height when water level is rising at a rate of 21 cm/min = 3.5 m and r' = radius when water level is rising at a rate of 21 cm/min

Now, by similar triangles, h/r = h'/r'

r' = h'r/h = 3.5 m × 1.5 m/12 m = 5.25 m²/12 m = 2.625 m = 262.5 cm

Since the rate at which the water level is rising is dh/dt = 21 cm/min, and the radius at that point is r' = 262.5 cm.

The net rate of increase of water is dV/dt = (πr'²dh/dt)/3

dV/dt = (π(262.5 cm)² × 21 cm/min)/3

dV/dt = (π(68906.25 cm²) × 21 cm/min)/3

dV/dt = 1447031.25π/3 cm³

dV/dt = 4545982.745/3 cm³

dV/dt = 1515327.582 cm³/min

Since dV/dt = k - 6800 cm³/min

k = dV/dt - 6800 cm³/min

k = 1515327.582 cm³/min - 6800 cm³/min

k = 1508527.582 cm³/min

So, the rate at which water is pumped in is 1508527.582 cm³/min

5 0
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