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Andrews [41]
4 years ago
8

In Windows Vista, which location contains the Printer link?

Computers and Technology
2 answers:
ipn [44]4 years ago
3 0
I believe it's B.) Printer and Faxes.
Sunny_sXe [5.5K]4 years ago
3 0
I just did on my windows vista,it's b
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The purpose of this act was to reduce workplace hazards and implement more safety and health programs for both employers and their employees.  

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Specific Instructions
Goryan [66]

In the most common use of the term, a class can be seen as a blueprint used to create objects. In other words, object(s) are created from a class in Java.

<h3>Creating a Class</h3><h3>Code:</h3>

import java.util.*;

class Card{

 private String suit;

 private int value;

 public Card(String s,int v){

   suit = s;

   value = v;

 }

 public String getSuit(){

   return suit;

 }

 public int getValue(){

   return value;

 }

 public void display(){

   System.out.println(value+"("+suit+")");

 }

}

class Deck{

 private ArrayList<Card> deck;

 private ArrayList<Card> drawn;

 public Deck(){

   deck = new ArrayList<Card>();

   drawn = new ArrayList<Card>();

   String[] arr = {"Club","Spade","Heart","Diamond"};

   for(String s : arr){

     for(int i=1;i<=13;i++){

       deck.add(new Card(s,i));

     }

   }

 }

 public void draw(){

   drawn.add(deck.get(0));

   deck.remove(0);

 }

 public void draw(int N){

   if(N > deck.size()){

     N = deck.size();

   }

   for(int i=0;i<N;i++){

     draw();

   }

 }

 public void showDrawn(){

   for(Card c : drawn){

     c.display();

   }

 }

 public void shuffle(){

   Collections.shuffle(deck);

 }

 public void restore(){

   restore(drawn.size());

 }

 public void restore(int N){

   if(N > drawn.size()){

     N = drawn.size();

   }

   for(int i=0;i<N;i++){

     deck.add(drawn.get(0));

     drawn.remove(0);

   }

 }

 public void showDeck(){

   for(Card c : deck){

     c.display();

   }

 }

}

class Test{

 public static void main(String[] args){

   Deck d = new Deck();

   System.out.println("Original deck\n");

   d.showDeck();

   d.draw(8);

   System.out.println("\nDeck after drawing 8 cards\n");

   d.showDeck();

   d.shuffle();

   System.out.println("\nDeck after shuffling\n");

   d.showDeck();

   d.restore();

   System.out.println("\nDeck after restoring cards\n");

   d.showDeck();

 }

}

<h3>Test Output:</h3>

C:\Users\hp\Desktop>java Test

Original deck

1(Club)

2(Club)

3(Club)

4(Club)

5(Club)

6(Club)

7(Club)

8(Club)

9(Club)

10(Club)

11(Club)

12(Club)

13(Club)

1(Spade)

2(Spade)

3(Spade)

4(Spade)

5(Spade)

6(Spade)

7(Spade)

8(Spade)

9(Spade)

10(Spade)

11(Spade)

12(Spade)

13(Spade)

1(Heart)

2(Heart)

3(Heart)

4(Heart)

5(Heart)

6(Heart)

7(Heart)

8(Heart)

9(Heart)

10(Heart)

11(Heart)

12(Heart)

13(Heart)

1(Diamond)

2(Diamond)

3(Diamond)

4(Diamond)

5(Diamond)

6(Diamond)

7(Diamond)

8(Diamond)

9(Diamond)

10(Diamond)

11(Diamond)

12(Diamond)

13(Diamond)

<h3>Draw action:</h3>

9(Club)

10(Club)

11(Club)

12(Club)

13(Club)

1(Spade)

2(Spade)

3(Spade)

4(Spade)

5(Spade)

6(Spade)

7(Spade)

8(Spade)

9(Spade)

10(Spade)

11(Spade)

12(Spade)

13(Spade)

1(Heart)

2(Heart)

3(Heart)

4(Heart)

5(Heart)

6(Heart)

7(Heart)

8(Heart)

9(Heart)

10(Heart)

11(Heart)

12(Heart)

13(Heart)

1(Diamond)

2(Diamond)

3(Diamond)

4(Diamond)

5(Diamond)

6(Diamond)

7(Diamond)

8(Diamond)

9(Diamond)

10(Diamond)

11(Diamond)

12(Diamond)

13(Diamond)

<h3 /><h3>Shuffling action:</h3>

12(Diamond)

8(Spade)

4(Spade)

6(Diamond)

10(Spade)

13(Club)

7(Heart)

13(Heart)

7(Diamond)

9(Heart)

11(Diamond)

5(Heart)

8(Diamond)

9(Diamond)

3(Spade)

13(Spade)

4(Heart)

2(Heart)

3(Heart)

5(Diamond)

11(Heart)

11(Club)

10(Club)

9(Club)

3(Diamond)

4(Diamond)

6(Spade)

9(Spade)

10(Heart)

11(Spade)

5(Spade)

12(Spade)

1(Spade)

6(Heart)

12(Heart)

13(Diamond)

1(Heart)

2(Diamond)

1(Diamond)

7(Spade)

12(Club)

10(Diamond)

2(Spade)

8(Heart)

  • Restore action

12(Diamond)

8(Spade)

4(Spade)

6(Diamond)

10(Spade)

13(Club)

7(Heart)

13(Heart)

7(Diamond)

9(Heart)

11(Diamond)

5(Heart)

8(Diamond)

9(Diamond)

3(Spade)

13(Spade)

4(Heart)

2(Heart)

3(Heart)

5(Diamond)

11(Heart)

11(Club)

10(Club)

9(Club)

3(Diamond)

4(Diamond)

6(Spade)

9(Spade)

10(Heart)

11(Spade)

5(Spade)

12(Spade)

1(Spade)

6(Heart)

12(Heart)

13(Diamond)

1(Heart)

2(Diamond)

1(Diamond)

7(Spade)

12(Club)

10(Diamond)

2(Spade)

8(Heart)

1(Club)

2(Club)

3(Club)

4(Club)

5(Club)

6(Club)

7(Club)

8(Club)

You can learn more about creating a class here brainly.com/question/10410845

6 0
2 years ago
Consider the following line of code: if (x &lt; 12 || (r – 3 &gt; 12)) Write three valid mutants of this ground string (based on
Nata [24]

Answer:

See explaination

Explanation:

Mutation Testing:

Mutation Testing is a type of software testing where we mutate (change) certain statements in the source code and check if the test cases are able to find the errors. It is a type of White Box Testing which is mainly used for Unit Testing. The changes in the mutant program are kept extremely small, so it does not affect the overall objective of the program.

We say a mutant is valid if it is syntactically correct. We say a mutant is useful if, in addition to being valid, its behavior differs from the behavior of the original program for no more than a small subset of program test cases.

VALID MUTANTS

1. if (x < 12 && (r – 3 > 12)) LOR

2. if (x < 12 || (r – 3 < 12)) ROR

3. if (x < 12 || (x – 3 < 12)) IVR

INVALID MUTANTS

1. if (x < 12 ||(r – 3 > 12) UPR

2. if (x < 12 (r – 3 < 12)) MLO

3. (x < 12 || (x – 3 < 12)) CSM

Note:

LOR: LOGICAL OPERATOR REPLACEMENT

ROR: RELATIONAL OPERATOR REPLACEMENT

IVR: INVALID VARIABLE REPLACEMENT

UPR: UNBALENCED PARANTHISIS REPLACEMENT

MLO: MISSING LOGICAL OPERATOR REPLACEMENT

CSM: CONTROL OPERATOR MISSING REPLACEMEN

4 0
3 years ago
4. How many times will the print statement be executed within the following nested for loops? Briefly explain how or show the ma
HACTEHA [7]

Print statements are used to display outputs

The number of times the nested loop will be executed is 43200

<h3>What are nested for loops?</h3>

Nested for loops are loops that are placed within another loop or loops

From the statement, we have the following loop conditions:

h = 1; h <= 12, m = 0; m <= 59 and s = 0; s <= 59

The above means that:

  • h = 12 --- the outer loop will be executed 12 times
  • m = 60 --- the middle loop will be executed 60 times
  • s = 60 --- the inner loop will be executed 60 times

So, the number of times the nested loop will be executed is:

Count = 12*60 *60

Count = 43200

Hence, the number of times the nested loop will be executed is 43200

Read more about loops at:

brainly.com/question/14284157

8 0
2 years ago
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