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joja [24]
3 years ago
10

Which one of the following is a functional requirement? Select one: a. None of the mentioned b. Robustness c. Maintainability d.

Portability
Computers and Technology
1 answer:
djyliett [7]3 years ago
5 0

Answer:

The correct answer to the question is option A "None of the mentioned"

Explanation:

Functional requirements describe the component of a system by verifying the functionality of the software, defines what function a system is likely to perform. It simply dictates to the system/software on how it must behave. For example, it commands software to display, for instance, User name, total orders placed, and a lot of other commands. It puts the computer/software to describe what the product has to do.

Nonfunctional requirements describe the general quality of a system describing how it works.

In the options above, Maintainability allows modification of applications, robustness allows a system to function well even after an interruption with an error command, and Portability allows easy running and the ability for software to be transferred easily, are all examples of non-functional requirements.

.

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find_cow(name, cows) Given a name and a Python list of Cow objects, return the Cow object with the specified name. If no such Co
nadya68 [22]

Using the computational knowledge in python it is possible to write a code that Given a name and a Python list of Cow objects

<h3>Writting the code in python:</h3>

<em>def load_cows(filename):</em>

<em>      cow_dict = dict()</em>

<em>    f = open(filename, 'r')</em>

<em> </em>

<em>    for line in f:</em>

<em>        line_data = line.split(',')</em>

<em>        cow_dict[line_data[0]] = int(line_data[1])</em>

<em>    return cow_dict</em>

<em>def greedy_cow_transport(cows, limit=10):</em>

<em>       trips = []</em>

<em>    cowsCopy = cows.copy()</em>

<em>    sortedCows = sorted(cowsCopy.items(), key=lambda x: x[1], reverse = True)</em>

<em>    while sum(cowsCopy.values()) > 0:</em>

<em>        ship = []</em>

<em>        total = 0</em>

<em>        for cow, value in sortedCows:</em>

<em>            if cowsCopy[cow] != 0 and value + total <= limit:</em>

<em>                ship.append(cow)</em>

<em>                total += value</em>

<em>                cowsCopy[cow] = 0</em>

<em>        trips.append(ship)</em>

<em>    return trips</em>

<em>def brute_force_cow_transport(cows,limit=10):</em>

<em>     trips = []</em>

<em>     possibilities = []</em>

<em>    for i in power_list:</em>

<em>        ship = []</em>

<em>        for j in i:</em>

<em>            ship_weights = []</em>

<em>            for k in j:</em>

<em>                ship_weights.append(cows[k])</em>

<em>                #print(ship_weights)</em>

<em>            ship.append(sum(ship_weights))</em>

<em>            #print(ship)</em>

<em>        if all(d <= limit for d in ship):</em>

<em>            possibilities.append(i)</em>

<em>      pruned_possibilities = []</em>

<em>    for k in possibilities:</em>

<em>        if k not in pruned_possibilities:</em>

<em>            pruned_possibilities.append(k)</em>

<em>    # now find the minimum list length:</em>

<em>    min_list_len = min(map(len, pruned_possibilities))</em>

<em>    for l in pruned_possibilities:</em>

<em>        if len(l) == min_list_len:</em>

<em>            return l</em>

<em>       </em>

<em>def compare_cow_transport_algorithms():</em>

<em>       greedy_start = time.time()</em>

<em>    greedy_results = greedy_cow_transport(cows, limit = 10)</em>

<em>    greedy_end = time.time()</em>

<em>    print('Greedy Algorithm time:', greedy_end -greedy_start)</em>

<em>    brute_force_start = time.time()</em>

<em>    brute_force_results = brute_force_cow_transport(cows, limit = 10)</em>

<em>    brute_force_end = time.time()</em>

<em>    print('Brute force time:', brute_force_end - brute_force_start)</em>

<em>    print('Greedy Algorithm results:', greedy_results)</em>

<em>    print('Number of trips returned by Greedy Algorithm:', len(greedy_results))</em>

<em>    print('Brute Force Algorithm results:', brute_force_results)</em>

<em>    print('Number of trips returned by Brute Force Algorithm:', len(brute_force_results))</em>

   

See more about python at brainly.com/question/13437928

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Which three major objects are built into the JavaScript language?
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3 0
3 years ago
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The japanese call the practice of stopping production when a defect occurs
lana66690 [7]

Answer:

Jidoka

Explanation:

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4 0
3 years ago
Green Field county stadium is planning to conduct a cricket match between two teams A and B. A large crowd is expected in the st
PtichkaEL [24]

Answer:

RS422-A or RS-485

Explanation:

Mode Name: RS422-A

Well, this is the electrical interface. The microprocessor covers the logics to electrical signals, and these electrical signals are then transmitted over a long distance, which is less than 4000 feet through RS422-A. And this is a half-duplex mode with the multidrop receiver and one transmitter at a time, in master-slave format. A receiver is a slave and the transmitter is a master. And there can only be one transmitter at a time. Here, a PC collects the videos from all cameras, through a unified system, and this PC is connected to numerous receivers which are the Screens. Parallel transmission cannot be done over a single line, and it's noisy as well, and hence we stick to serial mode. and here half-duplex as one at a time need to deliver, and not both. Hence, RS422-A is the first mode. which is a half-duplex serial transmission mode.

Reason 1:

It's noiseless

Reason 2:

The number of receivers can be as high as 10.

As the second alternative option:

Mode Name: RS-485

This is even better and allows receivers as high in number as 32, and hence is better than RS-422A. The maximum distance allowed is around 4000 feet, and the rest is the same as RS-422A. it also supports half-duplex.

Reason 1: It's less noisy and even better than RS422-A

Reason 2: number of receivers, and as high as 32 are allowed.

Remember, however, Ethernet is a low distance network, though it also supports collision detection, and multiple access/ carrier detection or CSMA/CD. However, for this question requirement RS-422A and RS-485 network interface will work fine. In the case of ethernet, we have an Ethernet Interface card, which works as an Ethernet network interface. However, Ethernet is a short distance, and will not work here.

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How would you cite the following source according to APA guidelines?
PSYCHO15rus [73]

B.Merriam-Webster's collegiate dictionary (10th ed.). (1993). Springfield, MA: Merriam-Webster.

In general, APA citations follow the format of;

<u>Contributors.(Date).Title. Publication Information</u>.  However, when there is no contributor information, write the name of the title first, followed by the date and the rest of the bibliographic data.



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