14, 21
Step-by-step explanation:
Let the two consecutive multiples be 7n and 7(n+1).
Now, it is given that:
(7n)² + [7(n+1)]² = 637
Simplifying,
49n² + (7n+7)² = 637
49n² + 49n² + 2(7n)(7) + 49 = 637
(as (x+y)² = x² + y² + 2xy)
98n² + 98n + 49 = 637
98n² + 98n - 588 = 0
Dividing by 98 to further simplify,
n² + n - 6 = 0
Factorising, we get
n² + 3n - 2n - 6 = 0
n(n+3) - 2(n+3) = 0
(n+3)(n-2) = 0
Therefore we get n = -3 or n = +2.
Hence, we get the consecutive multiples as 14 and 21.
Feel free to ask if you didn't understand any part.
Hope this helps! :D
Answer:
For every 7 small prizes won, there were 3 large prizes won.
ratio : 42:18 or 7:3
Answer:
6
Step-by-step explanation:
Substitute 1/4 with 8a. 8/4=2
Next, Substitute 10 for 0.5. 10/2=5
Finally, find the sum
(2-1)+5
6
Answer:A,D,E
Step-by-step explanation:
Just did the assignment
Answer:
im probably wrong but maybe the percentage or ratio
Step-by-step explanation:
