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Nadya [2.5K]
3 years ago
6

Write the equation of the line in point-slope form

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

The slope of this line is -1/2

Step-by-step explanation:

In order to find the value of any slope, you use the slope formula.

m (slope) = (y1 - y2)/(x1 - x2)

Then we pick two points in order to plug in. For the purpose of this graph, we'll use (0, -1) and (2, -2)

m (slope) = (y1 - y2)/(x1 - x2)

m (slope) = (-1 - -2)/(0 - 2)

m (slope) = 1/-2

m (slope) = -1/2

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Focus on number two ok
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Its simple, convert 1 and 2/3 into a fraction which is 5/3 and use KCF which is Keep Change and Flip,

How this works is that you keep the first fraction, then change the division sign to a multiplication sign (Change = change the sign into its oppisite) then flip the other fraction from being 5/3 into 3/5. And then you multiply top times top and bottom times bottom. After that you simplify if you can, Hope this helped!
7 0
3 years ago
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The graph below shows the velocity f(t) of a runner during a certain time interval:
Jlenok [28]
For this case, the first thing we must do is take into account the definition of the axes:
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3 years ago
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NO LINKS!! Please help me with these notes. Part 1a​
erik [133]

Answers:

When we evaluate a logarithm, we are finding the exponent, or <u>    power   </u>  x, that the  <u>   base   </u> b, needs to be raised so that it equals the <u>  argument   </u> m. The power is also known as the exponent.

5^2 = 25 \to \log_5(25) = 2

The value of b must be <u>   positive    </u> and not equal to <u>   1   </u>

The value of m must be <u>   positive   </u>

If 0 < m < 1, then x < 0

A <u>   logarithmic  </u>    <u>   equation  </u> is an equation with a variable that includes one or more logarithms.

===============================================

Explanation:

Logarithms, or log for short, basically undo what exponents do.

When going from 5^2 = 25 to \log_5(25) = 2, we have isolated the exponent.

More generally, we have b^x = m turn into \log_b(m) = x

When using the change of base formula, notice how

\log_b(m) = \frac{\log(m)}{\log(b)}

If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why b \ne 1

We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.

5 0
2 years ago
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Step-by-step explanation:

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