3y+2=5 linear equations
1 answer:
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The picture in the attached figure
we know that
m∠A+m∠B+m∠C=180°-----> by the sum of the internal angles of the triangle is 180 degrees
m∠A=25°
for m∠B=51°
find ∠C
∠C=180-[25+51]---------> m∠C=104°
for m∠B greater than 51°-------> m∠C must be less than 104°
for m∠B=57°
find m∠C
m∠C=180-[25+57]---------> m∠C=98°
for m∠B less than 57°-------> m∠C must be greater than 98°
therefore
98° < m∠C < 104°
we know that
m∠A+m∠B+m∠C=180°-----> by the sum of the internal angles of the triangle is 180 degrees
m∠A=25°
for m∠B=51°
find ∠C
∠C=180-[25+51]---------> m∠C=104°
for m∠B greater than 51°-------> m∠C must be less than 104°
for m∠B=57°
find m∠C
m∠C=180-[25+57]---------> m∠C=98°
for m∠B less than 57°-------> m∠C must be greater than 98°
therefore
98° < m∠C < 104°