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mafiozo [28]
2 years ago
13

PLS HELP IM SLOW Which graph represents the function ?

Mathematics
1 answer:
mars1129 [50]2 years ago
4 0

Answer:

B

Step-by-step explanation:

If you plug in x=1, then you get that f(1)=5, meaning that (1, 5) is a point on the graph.

Since graph B has the only line that passes through (1, 5), it must be the answer.

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|-4+5x|=16 <br> Pls help<br> Pls
Ronch [10]

Answer: i believe x = 4

Step-by-step explanation: 16 - |-4| which is adding two positives and that equals 20 so then its 5x = 20 divide 20 by 5 and you get 4

3 0
2 years ago
What is the equation for cx+4y=8t when your solving for x
Slav-nsk [51]
X = 8t/c - 4y/c

isolate the variable by dividing each side by factors that dont contain the variable
8 0
3 years ago
3y^2-9x=0 solve for y
Kamila [148]
1

Factor out the common term 3
3(y^2-3x)=0
2 Divide both sides by 3
y^2-3x=0
3 Add 3x to both sides
y^2=3x
4 Take the square root of both sides
y= positive or negative √3x

Hope I helped!
<span><span>
</span></span>
4 0
3 years ago
Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of
Shalnov [3]

Answer:

Owl= 67.14ft

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}

22^{\circ} 8'6'' = 22.135^{\circ}

30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}

30^{\circ} 40'30'' = 30.675^{\circ}

Considering Jason's position:

tan(22.135^{\circ}) = \frac{H}{x + 48}

Where x = distance between the tree and Alison

Make H the subject

H = (x + 48)tan(22.135^{\circ})

Considering Alison's position

tan(30.675^{\circ}) = \frac{H}{x}

Make H the subject

H = xtan(30.675^{\circ})

H = H

(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})

(x + 48) *0.4068 = x* 0.5932

Open bracket

x *0.4068 + 48 *0.4068 = 0.5932x

0.4068x + 19.5264 = 0.5932x

Collect Like Terms

-0.5932x+0.4068x = -19.5264

-0.1864x = -19.5264

0.1864x = 19.5264

Make x the subject

x = \frac{19.5264}{0.1864}

x = 104.76

Substitute 104.76 for x in H = xtan(30.675^{\circ})

H = 104.76 * tan(30.675^{\circ})

H = 104.76 * 0.5932

H = 62.14

The above represents the height of the tree.

The height of the owl is:

Owl= H + 5

Owl= 62.14 + 5

Owl= 67.14ft

7 0
2 years ago
El 2% que fraccion representa​
k0ka [10]
2/100 or 1/50 :p la respuesta
7 0
3 years ago
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