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saw5 [17]
3 years ago
14

Write an equivalent expression for 7+5k-2-3k+n. Which statements are true about the steps for writing the equivalent expression?

Check all that apply. Combine the constant terms by adding 7 and -2 The equivalent expression is 9+34- n.5k, and - 3k are like variable terms Combine the like variable terms by adding the coefficients 5k and -3k are like variable terms The constants 7 and 2 are like terms. The equivalent expression is 5+2k+n Combine the constant terms by adding 7 and 2 Mark this and retum Save and Exit Next Submit a (18​
Mathematics
2 answers:
VladimirAG [237]3 years ago
7 0

Answer:

can you like make this q more simple?

kondor19780726 [428]3 years ago
3 0

Answer:

a, d, e, f  g

Step-by-step explanation:

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Two lines, A and B, are represented by the equations given below:
slamgirl [31]

Answer:

(−5, −11), because the point satisfies both equations

Step-by-step explanation:

A solution to a system is always the ordered pair that satisfies both equations. So this explanation is the only one that would make sense.

5 0
4 years ago
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Write an expression for the sequence of operations described below.
alexandr402 [8]

Answer:

(m-8)+2

Step-by-step explanation:

hope this helps !

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3 years ago
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Can someone answer the question?​
fomenos

Answer:

\frac{\sqrt{3} }{3} }(cos(\frac{19\pi}{12})+isin(\frac{19\pi}{12}))

Step-by-step explanation:

Division of complex numbers in polar form is z_1/z_2=\frac{r_1}{r_2}cis(\theta_1-\theta_2) where z_1 and z_2 are the complex numbers being divided, r_1 and r_2 are the moduli, \theta_1 and \theta_2 are the arguments, and cis is shorthand for cos\theta+isin\theta. Therefore:

\frac{9(cos(\frac{11\pi}{6})+isin(\frac{11\pi}{6}))  }{3\sqrt{3}((cos\frac{\pi}{4})+isin(\frac{\pi}{4}))  }

\frac{9}{3\sqrt{3} }cis(\frac{11\pi}{6}-\frac{\pi}{4})

\frac{\sqrt{3} }{3} }cis(\frac{19\pi}{12})

\frac{\sqrt{3} }{3} }(cos(\frac{19\pi}{12})+isin(\frac{19\pi}{12}))

3 0
3 years ago
Express in standard form 24.12<br>​
ANTONII [103]

Answer:

2.412*10^{1}

Step-by-step explanation:

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3 years ago
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Factor: 15c^2 +37c +20
Masteriza [31]

Answer:

(5 c + 4) (3 c + 5)

Step-by-step explanation:

Factor the following:

15 c^2 + 37 c + 20

Factor the quadratic 15 c^2 + 37 c + 20. The coefficient of c^2 is 15 and the constant term is 20. The product of 15 and 20 is 300. The factors of 300 which sum to 37 are 12 and 25. So 15 c^2 + 37 c + 20 = 15 c^2 + 25 c + 12 c + 20 = 5 (5 c + 4) + 3 c (5 c + 4):

5 (5 c + 4) + 3 c (5 c + 4)

Factor 5 c + 4 from 5 (5 c + 4) + 3 c (5 c + 4):

Answer: (5 c + 4) (3 c + 5)

7 0
3 years ago
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