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3 years ago

Does this graph have 10 or 9 squares, 10 or 9 years, I think I might be going insane

Mathematics

1 answer:

Yuliya22 [10]3 years ago

8 0

Answer:

10 years

Step-by-step explanation:

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What is the percent of increase from 40.6 to 81.2?

crimeas [40]

Answer:

50?

Step-by-step explanation:

Pls, choose me as brainliest!

If I'm right, if not don't pick me

6 0

3 years ago

Evaluate the expression 5a + 5b. Let a = -6 and b = -5.

GrogVix [38]

<span>Evaluate the expression 5a + 5b. Let a = -6 and b = -5.

n = 5a + 5b
n = 5(-6) + 5(-5)
n = -30 + -25
n = -55

Hope this helps

</span>

8 0

4 years ago

Read 2 more answers

Emily estimated that there were 315 students at a soccer game the actual number of students at the game with 350 what was the pe

Readme [11.4K]

Answer:

About 11.10 Percent off. The change from 315 to 350 was an increase

Step-by-step explanation:

4 0

3 years ago

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

4 years ago

What is the constant in the expression?

Tpy6a [65]

If your answer was d) 3.6 , then you are correct!

7 0

3 years ago