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jolli1 [7]
3 years ago
6

Given a normally distributed data set of 500 observations measuring tree heights in a forest,

Computers and Technology
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

Since we have the normally distributed data set of the 500 observations. hence, according to the formula there will be 95% of the total observation within two standard deviations from the mean.

Hence, no. of observations will be= 95% of 500= 95 *5 = 475

Also remember standard deviation is (Xi-X')²

The standard deviation is the measurement of the dispersion of the data set from the mean. And its quite important in Data science.

Explanation:

The answer is self explanatory.

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Answer: i just learned something new.

Explanation:

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You are setting up your Windows computer to connect to the Internet and notice that when you type www.microsoft, the browser doe
Harrizon [31]

Answer:

Check your DNS settings

Explanation:

Different errors may occur when setting up your computer to connect to the internet, one of which is described in the question above.

The DNS (Domain Name System) is responsible for redirecting domain names to their physical IP address. Instead of remembering every IP address of sites you visit frequently, domain names are used for easy remembrance, the DNS makes the matching of domain names to IP addresses possible.

To change your DNS setting follow these steps:

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4 0
3 years ago
The purpose of this assignment is to determine a set of test cases knowing only the function’s specifications, reported hereaf
Nesterboy [21]

Answer:

The program is written using PYTHON SCRIPT below;

N=int(input(" Enter number of Rows you want:"))

M=[] # this for storing the matrix

for i in range(N):

l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))

M.append(l)

print("The 2D Matrix is:\n")

for i in range(N):

print(end="\t")

print(M[i])

W=[] # to store the first non zero elemnt index

T=[] # to store that value is positive or negative

L=len(M[0])

for i in range(N):

for j in range(L):

if (M[i][j]==0):

continue

else:

W.append(j) # If the value is non zero append that postion to position list(W)

if(M[i][j]>0): #For checking it is positive or negative

T.append(+1)

else:

T.append(-1)

break

print()

print("The first Non Zero element List [W] : ",end="")

print(W)

print("Positive or Negative List [T] : ",end="")

print(T)

Explanation:

In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.

It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.

5 0
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Stella is a bank executive. She is preparing a spreadsheet on the loan repayment schedules of customers. Which function can she
den301095 [7]

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HACTEHA [7]
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3 0
3 years ago
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