Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line = 
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512
Answer:
C. Layout Tab – Page setup group – Breaks – Next page button.
The answer is B. Windows icon
Answer:HUMAN RESOURCES AND PROCEDURE COMPONENTS
Explanation: Information systems are known to contain five components, these components help to describe the various aspects and importance of Information systems.
They Include The DATABASE AND DATA WAREHOUSE components(act as the store for all data), The COMPUTER HARDWARE(the physical components of the information systems such as computer harddrive etc)
THE COMPUTER SOFTWARE( the software which includes all the non physical and intangible assets of the information system),
THE HUMAN RESOURCES AND PROCEDURES COMPONENT( which gives instructions to the users).
THE TELECOMMUNICATIONS.
