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melamori03 [73]
3 years ago
15

Urgent!!! Brainliest ,25 points and a thanks for the first to answer.

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0

Answer:

1) 8

2) 6

3) 7

4) 0

5) 5

6) 1

7) 3

8) 2

9) -14

10) 12

11) -9

12) -6

13) -11

14) 1

15) -6

16) -12

17) -1/2

18) 9/11

19) 7/13

20) 9/7

21) -5/13

22) -13/25

Step-by-step explanation:

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X + y = 30<br><br> 2x + 4y = 84<br><br> Substitution<br> or<br> Elimination<br> I
miv72 [106K]

Answer:

(X,Y)(18,12)

Step-by-step explanation:

x + y = 30

2x + 4y = 84

___________

2x+2y=60

2x+4y=84

_________

-2y=-24/-2y

y=12

2x+4(12)=84

2x+48=84

2x=84-48

2x/2=36/2

X=18

3 0
3 years ago
Y=2x^2 - 10x + 13<br> Find the value.
pishuonlain [190]
Image of graph The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
6 0
3 years ago
How do I solve x^2+11x+28=0
Alex_Xolod [135]
Are you factoring ?

———————————-
3 0
3 years ago
The number 99 is increased to 104. What is the percentage by which the number was increased, to the nearest tenth of a percent?
Tanya [424]

Answer:

5.1

Step-by-step explanation:

I think im not shure

3 0
3 years ago
Read 2 more answers
Solve | x + 6| - 7 = 8
Alex

Answer:

x = 9,-21

Step-by-step explanation:

Given:

\displaystyle \large{|x+6|-7=8}

Transport -7 to add 8:

\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}

Cancel absolute sign and add plus-minus to 15:

\displaystyle \large{x+6=\pm 15}

Transport 6 to subtract ±15:

\displaystyle \large{x=\pm 15-6}

Consider:

\displaystyle \large{x= 15-6} or \displaystyle \large{x = -15-6}

\displaystyle \large{x=9} or \displaystyle \large{x=-21}

Solution:

\displaystyle \large{x = 9} or \displaystyle \large{x=-21}

__________________________________________________________

Second Method

Given:

\displaystyle \large{|x+6|-7=8}

Transport -7 to add 8:

\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}

Absolute Function Property:

\displaystyle \large{|x-a| = \begin{cases} x-a \ \ (x \geq a) \\ -x+a \ \ (x < a) \end{cases}}

Consider both intervals:

When x ≥ a then:

\displaystyle \large{|x+6|=15}\\\displaystyle \large{x+6=15}

Transport 6 to subtract 15:

\displaystyle \large{x=15-6}\\\displaystyle \large{x=9}

When x < a then:

\displaystyle \large{|x+6|=15}\\\displaystyle \large{-(x+6)=15}\\\displaystyle \large{-x-6=15}

Transport -6 to add 15:

\displaystyle \large{-x=15+6}\\\displaystyle \large{-x=21}

Transport negative sign to 21:

\displaystyle \large{x=-21}

Solution:

\displaystyle \large{x=9} or \displaystyle \large{x=-21}

__________________________________________________________

Let me know if you have any questions regarding this question, my answer or explanation. Hope this answer and explanation helps you and good luck with your assignment!

3 0
2 years ago
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