The answer is -125x^6
You do
(-5)^3 * (x^2)^3
The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined:

So the probability written as a simplified fraction is 1/2.
Answer:
52.5
Step-by-step explanation:
You divide 35 by 10 and then multiply 15 by that number
C because the y intercept is 0
Sounds like "exponential decay" is the answer your teacher is looking for
Expressions of the form y = a*b^x are considered decay equations or exponential decay equations if 0 < b < 1. So b can be between 0 and 1, but not equal to either endpoint.
Example: y = 3*0.5^x means we start off with 3 as the initial value, and then cut it in half repeatedly as x increases by 1 (eg: x = 0, x = 1, etc). This graph goes downhill as you read it from left to right.