Answer:
8x+2y+3x-18y+x^2
final answer: x^2+11x-16y
*edited*
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
1. 3.75+4.50=8.25- 5.25= $3 profit
She made 8.25 off selling bracelets to others, which adds money to her "account", but also spent money on crafting supplies, which results in her subtracting from her "account."
B=cost per boquet
v=cost per vase
3b+5v=25.75
8b+2v=29.00
use eliminateion
divide 2nd equation by 2
4b+v=14.50
multiply it by -5 and add to other equation to eliminate v
-20b-5v=-72.5
<span><u>3b+5v=25.75 +</u></span><u />
-17b+0v=-46.75
-17b=-46.75
divide both sides by -17
b=2.75
a boquet costs $2.75
Answer:the answer is D
Step-by-step explanation: I just took the test
