Your answer for 15 is D or C. For 16 I’m estimating 125?
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)
So the solid consist of 1 pentagon, 5 congruent equilateral triangle and 5 congruent squares and has 11 vertices so the number of edges of this solid is 20. I hope you are satisfied with my answer and feel free to ask form more if you have more clarifications.
Answer:
(c) {13,16,30}
Step-by-step explanation:
In order for the sides lengths to form a triangle, the sum of the shortest two must exceed the longest.
That will not be the case for ...
{13, 16, 30}
because 13 +16 = 29 < 30.
(13, 16, 30} could not form a triangle
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For more on the subject, see ...
brainly.com/question/26258903
The answer depends on knowing that 0.4444.... is equal to 4/9;
<span>the square root of 4/9 is 2/3 = 0.6666....</span>
