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blsea [12.9K]
3 years ago
12

We did not recieve a diagram for this question.

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0
If the line is tangent to circle at point A and the radius ( suppose AO) has a slope of 2.5 then a slope of the tangent line is :
\frac{-1}{2.5}= -0.4
Explanation: The product of slopes of two perpendicular lines is -1. To get second slope we have to divide -1 by the first one.
Answer:C) - 0.4
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salma went for a drive in her new car. she drove for 332.8 miles at a speed of 52 miles per hour. for how many hours did she dri
kkurt [141]
\begin{array}{ccc}52mi&-&1h\\332.8mi&-&xh\end{array}\ \ |cross\ multiply\\\\52x=1\cdot332.8\\\\52x=332.8\ \ \ |divide\ both\ sides\ by\ 52\\\\\boxed{x=6.4\ (h)}
3 0
3 years ago
How to factor 9x^4-6x^2y^4+y^89x4−6x2y4+y8
Virty [35]

Answer:

(3x^2-y^4)(3x^2-y^4)

Step-by-step explanation:

We'll assume the correct expression to be factored is

9x^4-6x^2y^4+y^8

One must try to find out if the expression is a perfect square. To test it, we'll take the square root of the first and the last term. If they are exact, we'll procceed with the next step

\sqrt{9x^4}=3x^2

\sqrt{y^8}=y^4

Since both are exact, we'll test if the middle term is twice the product of both square roots:

2(3x^2)(y^4)=6x^2y^4

We confirm the middle term equals the above expression. All tests confirm the original expression is

\left ( 3x^2-y^4 \right )^2

The required factoring is

(3x^2-y^4)(3x^2-y^4)

8 0
3 years ago
Graph DEFG after a rotation 270° counterclockwise
MrRa [10]
A 270 degree counter clockwise would be those same coordinates but negative numbers and right underneath the original
8 0
3 years ago
6x^2-5x+1<br><br> Factor polynomial
Tamiku [17]
6x²-5x+1
=6x²-3x-2x+1
=3x(2x-1)-1(2x-1)
=(3x-1)(2x-1)
8 0
4 years ago
3x+1 = y 2x+3y = 14<br> please explain the steps if you can as well
Likurg_2 [28]
3x + 1 = y
2x + 3y = 14

To solve this system of equations, we are going to use the substitution method.  Substitution the equation where the variable is isolated into the second equation.  In this system of equations, y is isolated, so we will replace y in the second equation with 3x + 1.

2x + 3y = 14
2x + 3(3x + 1) = 14
2x + 9x + 3 = 14
We will add the like terms and subtract 3 from both sides of the equation.
11x + 3 = 14
11x = 11
x = 1
In this system of equations, x is equal to 1.  Now we will go back and solve for y, plugging in 1 for x.
3(1) + 1 = y
2(1) + 3y = 14

3 + 1 = y
2 + 3y = 14

4 = y
3y = 2

4 = y
4 = y

The solution to this system of equations is (1, 4).

8 0
4 years ago
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