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murzikaleks [220]

2 years ago

10

When playing the integer game, the first two cards were -8 -10. What is the value of your hand? Write an equation to justify you

r answer.

1 answer:

patriot [66]2 years ago

3 0

Answer:

-18

Step-by-step explanation:

-8 + (-10)

-8-10

-18

Hope this HELPS

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Anyone that can help me with this?

mrs_skeptik [129]

If a rational function is not continuous, it'll be due to one of two reasons. Either it has a hole, or it has an asymptote. Plug in -5 for x in the denominator of the rational function. What do you get? You get zero in the denominator, meaning the function is undefined at x=-5.

4 0

3 years ago

Simplify the expression,<br> -2.75 +0.31 - 16-3

dalvyx [7]

Answer:

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Step-by-step explanation:

8 0

2 years ago

In △ABC, point D∈ AC with AD:DC=4:3, point E∈ BC so that BE:EC=1:5. If ACDE=5 in2, find ABDC, AABD, and AABC.

Kaylis [27]

Answer:

ar ΔBDC=6 $in^2$

ar ΔABD=8 $in^2$

ar ΔABC=14 $in^2$

Explanation:

Please take a look of attach figure.

We are given area of triangle ar ΔCDE=5 $in^2$

ar ΔCDE= $\frac{1}{2}\times DN\times EC$ ------------(1)

ar ΔBDE= $\frac{1}{2}\times DN\times BE$ ------------(2)

Divide eq(2) by eq(1) and we get,

$\frac{ar\ ΔBDE}{ar\ ΔCDE}=\frac{BE}{EC}$

$\frac{ar\ ΔBDE}{5}=\frac{1}{5}$

So, ar ΔBDE=1 $in^2$

ar ΔBDC=ar ΔBDE+ ar ΔCDE

ar ΔBDC=1+5 = 6 $in^2$

Similarly,

$\frac{ar\ ΔABD}{ar\ ΔBDC}=\frac{AD}{DC}$

$\frac{ar\ ΔABD}{6}=\frac{4}{3}$

ar ΔABD=8 $in^2$

ar ΔABC=ar ΔABD + ar ΔBDC

ar ΔABC=8+6 = 14 $in^2$

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3 years ago

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aleksklad [387]

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BaLLatris [955]

0/1

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