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3 years ago

Using three or more complete sentences, describe a unitary government system.

1 answer:

5 0

Unsourced material may be challenged and removed. A national unity government, government of national unity (GNU), or national union government is a broad coalition government consisting of all parties (or all major parties) in the legislature, usually formed during a time of war or other national emergency.

Monkey

2 years ago

Thank you so much this really helped me

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Please help me with number 8

Vika [28.1K]

The answer is negative 3

8 0

3 years ago

If a bucket holds 2 2/4 gallons of water. And the bucket is 5/8 full. how full is the bucket

s344n2d4d5 [400]

Multiply 2 2/4 by 5/8.

First, simplify 2 2/4 to 2 1/2.

Then, convert to improper form (5/2).

5/2 x 5/8 = 25/16

answer: 1 9/16 gallons of water

8 0

2 years ago

CAN SOMEONE PLS HELP MEEEEEEE

k0ka [10]

9514 1404 393

Answer:

6x +y = -6
6x -y = 8
5x +y = 13

Step-by-step explanation:

To rewrite these equations from point-slope form to standard form, you can do the following:

eliminate parentheses
subtract the x-term
subtract the constant on the left
if the coefficient of x is negative, multiply by -1

Of course, any operation you do must be done <em>to both sides of the equation</em>.

1. y -6 = -6(x +2)

y -6 = -6x -12 . . . . . eliminate parentheses

6x +y -6 = -12 . . . . . add 6x

6x +y = -6 . . . . . . . . add 6

2. y +2 = 6(x -1)

y +2 = 6x -6

-6x +y +2 = -6

-6x +y = -8

6x -y = 8 . . . . . . . . multiply by -1

3. y -3 = -5(x -2)

y -3 = -5x +10

5x +y -3 = 10

5x +y = 13

_____

<em>Additional comment</em>

The "standard form" of a linear equation is ax+by=c for integers a, b, c. The leading coefficient (generally, 'a') should be positive, and all coefficients should be mutually prime (have no common factors). That is why we multiply by -1 in problem 2.

7 0

2 years ago

Please help me I really don't wanna fail

Ludmilka [50]

Answer:

the answer for under n would be 14

6 0

3 years ago

Read 2 more answers

How do you solve this?

k0ka [10]

$x^2-3x-4=0\\\\x^2-2x\cdot\frac{3}{2}=4\ \ \ /+(\frac{3}{2})^2\\\\x^2-2x\cdot\frac{3}{2}+(\frac{3}{2})^2=4+(\frac{3}{2})^2\\\\(x-\frac{3}{2})^2=4+\frac{9}{4}\\\\(x-\frac{3}{2})^2=\frac{16}{4}+\frac{9}{4}\\\\(x-\frac{3}{2})^2=\frac{25}{4}\\\\x-\frac{3}{2}=\pm\sqrt\frac{25}{4}$

$x-\frac{3}{2}=\pm\frac{\sqrt{25}}{\sqrt4}\\\\x-\frac{3}{2}=\pm\frac{5}{2}\\\\x-\frac{3}{2}=-\frac{5}{2}\ or\ x-\frac{3}{2}=\frac{5}{2}\\\\x=-\frac{5}{2}+\frac{3}{2}\ or\ x=\frac{5}{2}+\frac{3}{2}\\\\x=-\frac{2}{2}\ or\ x=\frac{8}{2}\\\\x=-1\ or\ x=4$

5 0

3 years ago

Read 2 more answers