(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
A.0 I think ................
Step 1: Find the slope
(y-y)/(x-x) = (8-8)/(9+4) = 0
Step 2: Substitute into the slope intercept equation
y - y = m(x - x)
y - 8 = 0(x - 9)
If the problem just wants plain, slope intercept form, then this is your answer.
If not, y = 8
Answer: see proof below
<u>Step-by-step explanation:</u>
