Answer:
Step-by-step explanation:
(10 pushups)/(25 sec) = (⅖ pushup)/sec
Or,
(25 sec)/(10 pushups) = (2.5 sec)/pushup
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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Answer:
try 7,920 miles
Step-by-step explanation:
I just took 8,578 - 658 and got 7,920.
The graph shown is decreasing.