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defon
3 years ago
5

Assume that an int variable x that has already been declared,and initialized to a non-negative value. write an expression whose

value is the last (rightmost) digit of x.
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer:

x % 10

Step-by-step explanation:

Given that an int variable x has been declared and initialized to a non-negative value. In order to determine the last digit of x, we need to find the remainder of x when divided by 10. In programming languages such an operation is represented using the modulus(%) operator. So the required expression is given by x%10.

For example , if x = 29, then x%10 will be 9, that is remainder of 29 when divided by 10.

pochemuha3 years ago
3 0

We know that an int variable, x, has been declared

It has been assigned a non-negative value

We need to write an expression that extracts the rightmost digit of x

The logic for doing so would be to divide the number by 10, and checking the remainder. The remainder will always yield the rightmost digit. In case the number is a multiple of 10 then the remainder would be 0 (which would be the rightmost digit of the number)

So we can do so by:

int y = x % 10;

% is the modulo function, which returns the remainder after carrying out division

we have declared y to be int, as % will always return int values.

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Does anyone know how to do this/have the answer? PLEASE
podryga [215]

15: You solve problems like this by finding the probability of each case, and then multiplying them all. For each of the last 4 question, she has probability 1/2 of guessing right. So, she guessed 4 consecutive questions with probability

\left(\dfrac{1}{2}\right)^4=\dfrac{1}{16}

16: Like before: you have pick a king with probability 4/52 = 1/13 (there are four kings - one for each suit, out of 52 cards in a standard deck), and you pick "I" from "INCREDIBLE" with probability 2/10 = 1/5 (there are two "I"s out of 10 letters). So, the probability of picking a king and then an "I" is

\dfrac{1}{13}\cdot\dfrac{1}{5}=\dfrac{1}{65}

17-20: The important bit of information here is that you replace the first ball. So, the first and second pick follow the exact same probability distribution, because they basically are two repetitions of the same experiment. So, for example, in ex. 17, the first ball is even with probability 15/30 = 1/2 (there are 15 even balls out of 30). Then, you have again probability 15/30 = 1/2 to pick an odd ball (there are also 15 odd balls out of 30). So, the probability of picking an even ball, replace it, and pick an odd ball is

\dfrac{1}{2}\cdot\dfrac{1}{2}=\dfrac{1}{4}

Exercises 18 to 20 follow the same scheme: find out the probability of the two events and multiply them.

21-26: Not we DON'T replace the balls, so the second pick will suffer the effects of the first one. Let's dive into ex. 21 for example. For the first pick, we want a 2-digits number. There are 21 of such balls (all balls except balls 1 to 9), so we pick a 2-digits ball with probability 21/30 = 7/10. For the second pick, we want the balls number 4. But we have to assume that we already picked the first ball, and we picked a 2-digits ball. So, for the second pick, we're choosing from a bag with 29 balls, and there is only one ball labeled 4. So, we pick the ball number 4 with probability 1/29. We deduce that the two events happen one after the other with probability

\dfrac{7}{10}\cdot\dfrac{1}{29}=\dfrac{7}{290}

Exercises 22 to 26 are similar: you find out the probability of the first event, and then you consider the new environment (i.e. you keep track of the first pick) when it comes to the probability distribution for the second pick).

5 0
3 years ago
21.6% can u please change this to a decimal and include the work like I had it in the little picture . Plss and thank you .
Nadya [2.5K]

Answer:

<em>Decimal Form; 0.216 </em>

Step-by-step explanation:

If we are to convert to a decimal, move the decimal point 2 to the left, as such;

21.6 percent ( % ), ⇒ move decimal place two to the left,

<em>Decimal Form; 0.216 </em>

4 0
4 years ago
What is the volume of a square pyramid with a base length of 6cm and a height of 9cm?
emmainna [20.7K]
Answer:
Volume = 108 cm ³

Explanation:
For a square pyramid, the volume can be calculated as follows:
Volume = \frac{1}{3} * area of base * height
Volume = \frac{1}{3} * side² * height
We have:
side length = 6 cm
height = 9 cm
Therefore:
Volume = \frac{1}{3} * 36 * 9 = 108 cm ³

Hope this helps :)
8 0
4 years ago
100 points &amp; brainliest if you get it correct!
PolarNik [594]

Answer:

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Step-by-step explanation:

Question 1:

B1: $12.19 / 5.7 lbs = about $2.14

B2: $2.15

$2.14 < $2.15

4 0
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Answer:

x=15

Step-by-step explanation:

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8 0
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